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json - 使用 SwiftyJSON 解析具有相似元素的 JSON

问题描述

我有这种类型的 JSON（只是一个简短的示例）：

"orderProducts": [
        {
            "id": 135,
            "order_id": 39,
            "product_id": 49,
            "product_code": "",
            "size_id": 13,
            "quantity": 2,
            "product": {
                "id": 49,
                "code": "",
                "factory_id": 2,
                "product_category_id": 1,
                "sex_id": null,
                "season_id": null,
                "product_type_id": null,
                "type_id": null,
                "color_id": null,
                "year_id": null,
                "image_1": "bceef8b28ae2a1797ca0c6300021100d.jpeg",
                "image_2": "",
                "image_3": "",
                "notes": "",
                "status": 10
            }
        },
        {
            "id": 136,
            "order_id": 39,
            "product_id": 49,
            "product_code": "",
            "size_id": 14,
            "quantity": 3,
            "product": {
                "id": 49,
                "code": "",
                "factory_id": 2,
                "product_category_id": 1,
                "sex_id": null,
                "season_id": null,
                "product_type_id": null,
                "type_id": null,
                "color_id": null,
                "year_id": null,
                "image_1": "bceef8b28ae2a1797ca0c6300021100d.jpeg",
                "image_2": "",
                "image_3": "",
                "notes": "",
                "status": 10
            }
        },
        {
            "id": 137,
            "order_id": 39,
            "product_id": 48,
            "product_code": "",
            "size_id": null,
            "quantity": 24,
            "product": {
                "id": 48,
                "code": "",
                "factory_id": 2,
                "product_category_id": null,
                "sex_id": null,
                "season_id": null,
                "product_type_id": null,
                "type_id": null,
                "color_id": null,
                "year_id": null,
                "image_1": "2aee8660b4218bf549c2d9345beb2a01.jpeg",
                "image_2": "",
                "image_3": "",
                "notes": "",
                "status": 10
            }
        }]

我需要解析的项目是product_id：size_id和quantity。为此，我创建了这个结构：

struct Products {
    let id: String
    let quantities: [(sizeId: String, quantity: String)]?

    init(id: String, quantities: [(sizeId: String, quantity: String)]) {
        self.id = id
        self.quantities = quantities
    }
}

我想要达到的最终结果是：

[Products(id: "49", quantities: [(sizeId: "13", quantity: "2"), (sizeId: "14", quantity: "3")]), 
Products(id: "48", quantities: [(sizeId: "null", quantity: "24")])]

使用 SwiftyJSON 解析时，我这样做：

for productId in products.arrayValue {
                        self.productWithQuantites.append(Products(id: productId["product_id"].stringValue,
                                                                  quantities: [(sizeId: productId["size_id"].stringValue,
                                                                                quantity: productId["quantity"].stringValue)]))

                    }

但我明白了：

    [Products(id: "49", quantities: [(sizeId: "13", quantity: "2")]),
Products(id: "49", quantities: [(sizeId: "14", quantity: "3")],
Products(id: "48", quantities: [(sizeId: "null", quantity: "24")])]

我做错了什么？如何将新数量附加到现有元素？将感谢代码示例或任何帮助。

标签： jsonswiftswifty-json

解决方案

在 Swift 4中，该协议SwiftyJSON已过时。Codable

不要在结构中使用元组，将值分开并Product根据产品 ID 将（最好使用单数形式）实例分组到字典中。

假设data包含 JSON 原始数据创建这些微小的结构

struct Root : Decodable {
    let orderProducts : [Product]
}

struct Product: Decodable {
    let id : Int
    let productId : Int
    let sizeId : Int?
}

将 JSON 解码为结构并将数组与Dictionary(grouping:by:)

do {
   let decoder = JSONDecoder()
   decoder.keyDecodingStrategy = .convertFromSnakeCase
   let result = try decoder.decode(Root.self, from: data)
   let groupedDictionary = Dictionary(grouping: result.orderProducts, by: {$0.productId})
   print(groupedDictionary)
   // [49: [Product(id: 135, productId: 49, sizeId: Optional(13)), 
   //      Product(id: 136, productId: 49, sizeId: Optional(14))], 
   //  48: [Product(id: 137, productId: 48, sizeId: nil)]]

} catch { print(error) }

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