android - 使用 Cipher.doFinal() 进行 RSA 解密不会恢复原始纯文本
问题描述
从原始资源文件生成公钥/私钥对并使用它们在 android 应用程序中加密/解密非常简单。但是,以下代码在 VirtualBox 中使用 Android-x86-v4.4.4 模拟器运行时无法正确恢复纯文本。谁能指出这段代码有什么问题(它不会给出任何错误或产生任何异常):(更改为 Cipher.getInstance("RSA/NONE/NoPadding") 也无济于事)
PublicKey mPublicKey = null;
PrivateKey mPrivateKey = null;
String mPlainText = "The quick brown fox jumped over the lazy dog" ;
byte[] mEncryptText = null;
byte[] mDecryptText = null;
try {
InputStream mIS = getResources().openRawResource(R.raw.test1_public_key);
DataInputStream dis = new DataInputStream(mIS);
byte [] keyBytes = new byte [(int) mIS.available()];
dis.readFully(keyBytes);
dis.close();
mIS.close();
X509EncodedKeySpec mX509KeySpec = new X509EncodedKeySpec(keyBytes);
mPublicKey = (KeyFactory.getInstance("RSA")).generatePublic(mX509KeySpec);
Toast.makeText(this, "Publickey generated", Toast.LENGTH_LONG).show();
}
catch(Exception e){
Log.e("onButtondecrypt", "exception", e);
Log.e("onButtondecrypt", "exception: " + Log.getStackTraceString(e));
}
try {
InputStream mIS = getResources().openRawResource(R.raw.test1_private_key);
DataInputStream dis = new DataInputStream(mIS);
byte [] keyBytes = new byte [(int) mIS.available()];
dis.readFully(keyBytes);
dis.close();
mIS.close();
PKCS8EncodedKeySpec mPKCS8keySpec = new PKCS8EncodedKeySpec(keyBytes);
mPrivateKey = (KeyFactory.getInstance("RSA")).generatePrivate(mPKCS8keySpec);
Toast.makeText(this, "PRIVATE key generated", Toast.LENGTH_LONG).show();
}
catch(Exception e){
Log.e("onButtondecrypt", "exception", e);
Log.e("onButtondecrypt", "exception: " + Log.getStackTraceString(e));
}
Toast.makeText(this, mPlainText, Toast.LENGTH_LONG).show();
Toast.makeText(this, "Encrypting with Publickey ...", Toast.LENGTH_LONG).show();
try {
Cipher cipher = Cipher.getInstance("RSA");
cipher.init(Cipher.ENCRYPT_MODE, mPublicKey);
mEncryptText = cipher.doFinal(mPlainText.getBytes());
Toast.makeText(this, mEncryptText.toString(), Toast.LENGTH_LONG).show();
}
catch(Exception e){
Log.e("onButtondecrypt", "exception", e);
Log.e("onButtondecrypt", "exception: " + Log.getStackTraceString(e));
}
Toast.makeText(this, "Decrypting with PRIVATE key ...", Toast.LENGTH_LONG).show();
try {
Cipher cipher = Cipher.getInstance("RSA");
cipher.init(Cipher.DECRYPT_MODE, mPrivateKey);
mDecryptText = cipher.doFinal(mEncryptText);
Toast.makeText(this, mDecryptText.toString(), Toast.LENGTH_LONG).show();
}
catch(Exception e){
Log.e("onButtondecrypt", "exception", e);
Log.e("onButtondecrypt", "exception: " + Log.getStackTraceString(e));
}
谢谢大家。
解决方案
字符串转换为 byte[] 的方式是错误的,反之亦然。正确的方法是
byte[] st = txt.getBytes("UTF-8");
和
String s = new String(bytes);
因此,加密/解密是正确的,只有吐司显示不正确。
推荐阅读
- java - 如何将 PDDocument 的所有页面保存在单独的 .pdf 文件中?
- bit - Bitsrc:错误:标记组件时出现未知对象类型“窗口”
- java - 方法体内的 lambda 表达式
- php - 从 woocommerce 页面中删除重力形式动作
- java - 如何在自动化中找到类似于 getText() 的元素定位器
- angular - 在 ng2-charts 中隐藏三个工具提示之一
- anychart - 如何将 xGrid 线与数据点对齐?
- python - 根据值列移动文件python
- regex - Velocity 中的 Regex 和 ReplaceAll 提取文本
- java - 从 Firebase 中检索数据