python - Kivy 时钟和条件语句
问题描述
我创建了变量 timer_loop 来连续运行。我想用其他变量做条件语句,但我做不到。下面是一个例子,如果开关被激活,我会尝试每 30 分钟“做一些事情”。任何反馈将不胜感激:)
from kivy.app import App
from kivy.lang import Builder
from kivy.clock import Clock
import datetime
import time
theRoot = Builder.load_string('''
StackLayout:
orientation: 'lr-tb'
padding: 10
spacing: 5
Label:
text: "Zone 1 Valve"
size_hint: .5, .1
Switch:
id: switch_id
on_active: app.switch_on1(self, self.active)
size_hint: .5, .1
''')
class theApp(App):
def build(self):
Clock.schedule_interval(self.timer_loop, 2)
return theRoot
def timer_loop(self, dt):
now_minute = int(time.strftime("%M"))
if switch_on1.active & now.minute ==30 : # how do I use the varible switch_on1 in this loop for conditonal statements???
print("Do something")
else:
print("Do nothing")
def switch_on1(self, instance, value):
if value is True:
print("Switch 1 On")
else:
print("Switch 1 Off")
if __name__ == '__main__':
theApp().run()
解决方案
总是建议将一个类视为一个黑盒,我们可以建立输入并获得输出,并且在 kivy 中可以通过属性来完成,例如在这种情况下,您创建StackLayout
反映 switch_id 的 active 属性的 active 属性,并且因为theRoot
是StackLayout
从 python 中可见的对象,所以我们使用它:
from kivy.app import App
from kivy.lang import Builder
from kivy.clock import Clock
import time
theRoot = Builder.load_string('''
StackLayout:
active: switch_id.active # <---
orientation: 'lr-tb'
padding: 10
spacing: 5
Label:
text: "Zone 1 Valve"
size_hint: .5, .1
Switch:
id: switch_id
size_hint: .5, .1
''')
class theApp(App):
def build(self):
Clock.schedule_interval(self.timer_loop, 2)
return theRoot
def timer_loop(self, dt):
now_minute = int(time.strftime("%M"))
if theRoot.active and now_minute == 30: # <---
print("Do something")
else:
print("Do nothing")
if __name__ == '__main__':
theApp().run()
正如您意识到的那样,没有必要使用switch_on1
,因为主要条件是触发计时器。