java - 尝试在 Spring Boot 中从 null 一对一属性分配 id
问题描述
我在spring boot中有这个错误:
试图从空的一对一属性 [com.endoorment.models.entity.ActionLang.action] 分配 id
我的代码:
@Embeddable
public class ActionLangId implements Serializable {
private static final long serialVersionUID = 1 L;
@NotNull
@Column(name = "actions_id")
private Integer actionId;
@NotNull
@Column(name = "langs_id")
private Integer langId;
public ActionLangId() {}
public ActionLangId(Integer actionId, Integer langId) {
super();
this.actionId = actionId;
this.langId = langId;
}
public Integer getActionId() {
return actionId;
}
public void setActionId(Integer actionId) {
this.actionId = actionId;
}
public Integer getLangId() {
return langId;
}
public void setLangId(Integer langId) {
this.langId = langId;
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass())
return false;
ActionLangId that = (ActionLangId) o;
return Objects.equals(actionId, that.actionId) &&
Objects.equals(langId, that.langId);
}
@Override
public int hashCode() {
return Objects.hash(actionId, langId);
}
}
@Entity
@Table(name = "actions_langs")
public class ActionLang {
@EmbeddedId
private ActionLangId id;
@ManyToOne(fetch = FetchType.LAZY)
@MapsId("actionId")
@JoinColumn(name = "actions_id")
private Action action;
@ManyToOne(fetch = FetchType.LAZY)
@MapsId("langId")
@JoinColumn(name = "langs_id")
private Lang lang;
@NotNull(message = "null")
@Size(max = 45, message = "short")
private String name;
public ActionLang() {}
public ActionLang(ActionLangId actionlangid, String name) {
this.id = actionlangid;
this.name = name;
}
public ActionLangId getId() {
return id;
}
public void setId(ActionLangId id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Override
public String toString() {
return "ActionLang [id=" + id + ", name=" + name + "]";
}
}
服务:
@Transactional
public ActionLang saveAction(Integer idlang, String name) {
Integer id = actionRepository.findActionId();
Action action = new Action(id);
actionRepository.save(action);
ActionLang actionlang = new ActionLang(new ActionLangId(id, idlang), name);
actionlangRepository.save(actionlang);
return actionlang;
}
Structure actionlang: {
"id": {
"actionId": 2,
"langId": 1
},
"name": "hkjhlhklhkllñkñl"
谢谢
解决方案
我的解决方案,
实体动作:
@Entity
@Table(name = "actions")
public class Action {
@Id
private Integer id;
@OneToMany(mappedBy = "action")
private List<ActionLang> actionlang = new ArrayList<>();
public Action() { }
public Action(Integer id) {this.id = id;}
public Integer getId() {return id;}
public void setId(Integer id) {this.id = id;}
public List<ActionLang> getActionLang() {return actionlang;}
public void addActionLang(ActionLang actionlang) {
this.actionlang.add(actionlang);
}
public void removeActionLang(ActionLang actionlang) {
this.actionlang.remove(actionlang);
}
@Override
public String toString() {return "id: " + id ;}
}
实体动作语言,
@Entity
@Table(name = "actions_langs")
public class ActionLang {
@EmbeddedId
private ActionLangId id;
@ManyToOne(fetch = FetchType.LAZY)
@MapsId("actionId")
@JoinColumn(name = "actions_id", nullable = false)
@OnDelete(action = OnDeleteAction.CASCADE)
@JsonIgnore
private Action action;
@ManyToOne(fetch = FetchType.LAZY)
@MapsId("langId")
@JoinColumn(name = "langs_id", nullable = false)
@OnDelete(action = OnDeleteAction.CASCADE)
@JsonIgnore
private Lang lang;
@NotNull(message="null")
@Size(max = 45, message="short")
private String name;
public ActionLang() {}
public ActionLang(ActionLangId actionlangid, String name) {
this.id = actionlangid;
this.name = name;
}
public ActionLangId getId() {return id;}
public String getName() {return name;}
public void setName(String name) {this.name = name;}
public void setId(ActionLangId id) {this.id = id;}
public Action getAction() {return action;}
public void setAction(Action action) {this.action = action;}
public Lang getLang() {return lang;}
public void setLang(Lang lang) { this.lang = lang; }
@Override
public String toString() {return "ActionLang [id=" + id + ", name=" + name + "]"; }
}
服务
@Component
public class ActionDAOService {
@Autowired
private IActionDao actionRepository;
@Autowired
private IActionLangDao actionlangRepository;
@Transactional
public Action saveAction(Integer idlang, String name){
Lang lang = new Lang();
lang.setId(idlang);
Integer id = actionRepository.findActionId();
if(id == null) {
id=(Integer) 1;
}
Action action = new Action(id);
actionRepository.save(action);
ActionLang actionlang = new ActionLang(new ActionLangId(id, idlang),name);
action.addActionLang(actionlang);
actionlang.setAction(action);
actionlang.setLang(lang);
actionlangRepository.save(actionlang);
return action;
}
}
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