首页 > 解决方案 > 给定“整数”、“App\Entity\Entreprise”类型的预期参数

问题描述

我使用两个实体:stagiaire 和 entreprise。每个 stagiaire 都有一个企业。我只需要将 id entreprise 保存在 stagiaire 表中。当我创建一个新的stagiaire,为他选择一个企业并保存表格时,我有以下错误

“stagiaire 控制器中的“整数”类型的预期参数:“App\Entity\Entreprise”给定

这是 stagiaire 实体的代码:

namespace App\Entity;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity(repositoryClass="App\Repository\StagiaireRepository")
 */

class Stagiaire
{
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer", nullable=false)
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="IDENTITY")
     */
    private $id;

    /**
     * @var string
     *
     * @ORM\Column(name="civilite", type="string", length=3, nullable=false)
     */
    private $civilite = 'Mr';

    /**
     * @var string
     *
     * @ORM\Column(name="nom", type="string", length=24, nullable=false)
     */
    private $nom;

    /**
     * @var string
     *
     * @ORM\Column(name="prenom", type="string", length=16, nullable=false)
     */
    private $prenom;

    /**
     * @ORM\ManyToOne(targetEntity="App\Entity\Entreprise")
     * @ORM\JoinColumn(nullable=false)
     */
    private $entreprise;

    /**
     * @var string
     *
     * @ORM\Column(name="status", type="string", length=12, nullable=false)
     */
    private $status;

    public function __construct()
  {
    //$this->date       = new \Datetime();
    //$this->entreprise = new ArrayCollection();
  }

    public function getId(): ?int
    {
        return $this->id;
    }

    public function getCivilite(): ?string
    {
        return $this->civilite;
    }

    public function setCivilite(string $civilite): self
    {
        $this->civilite = $civilite;

        return $this;
    }

    public function getNom(): ?string
    {
        return $this->nom;
    }

    public function setNom(string $nom): self
    {
        $this->nom = $nom;

        return $this;
    }

    public function getPrenom(): ?string
    {
        return $this->prenom;
    }

    public function setPrenom(string $prenom): self
    {
        $this->prenom = $prenom;

        return $this;
    }

    public function getEntreprise(): ?int
    {
        return $this->entreprise;
    }

    public function setEntreprise(int $entreprise): self
    {
        $this->entreprise = $entreprise;

        return $this;
    }

    public function getStatus(): ?string
    {
        return $this->status;
    }

    public function setStatus(string $status): self
    {
        $this->status = $status;

        return $this;
    }

这是表单的代码:

use App\Entity\Stagiaire;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;
use Symfony\Component\Form\Extension\Core\Type\FormType;
use Symfony\Component\Form\Extension\Core\Type\ChoiceType;
use Symfony\Component\Form\Extension\Core\Type\SubmitType;
use Symfony\Component\Form\Extension\Core\Type\TextType;
use Symfony\Bridge\Doctrine\Form\Type\EntityType;

class StagiaireType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $choicesCivil = [
            'Mr' => '1',
            'Mme' => '2'
        ];
        $choicesStatus = [
            'Gérant' => '1',
            'Salarié' => '2'
        ];

        $builder
            ->add('civilite', ChoiceType::class, [
                'data' => '1', // cochée par défaut
                'choices' => $choicesCivil,
                'expanded' => true,  // => boutons
                'label' => 'Civilité',
                'multiple' => false
            ])
            ->add('nom')
            ->add('prenom')
            ->add('entreprise', EntityType::class, array(
                'class'         => 'App:Entreprise',
                'placeholder'   => 'Choisir une entreprise',
                'choice_label'  => 'enseigne',
            ))
            ->add('status', ChoiceType::class, [
                'data' => '1', // cochée par défaut
                'choices' => $choicesStatus,
                'expanded' => true,  // => boutons
                'label' => 'Statut',
                'multiple' => false
            ])
            ->add('create', SubmitType::class, ['label' => 'Enregistrer', 'attr' => ['class' => 'btn btn-primary']]);
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'data_class' => Stagiaire::class,
        ]);
    }
}

这是控制器:

namespace App\Controller;

use Symfony\Bundle\FrameworkBundle\Command\ContainerAwareCommand;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;

use App\Entity\Stagiaire;
use App\Entity\Entreprise;
use App\Repository\StagiaireRepository;
use App\Form\StagiaireType;

class StagiaireController extends Controller
{
    public function fStagiaire($id,$cat,$action, Request $request)
    {
        if ($action=='insert') {
            $stagiaire = new Stagiaire();
        }
        elseif($action=='update' || $action=='delete') {
            $stagiaire = $this->getDoctrine()
              ->getManager()
              ->getRepository('App:Stagiaire')
              ->find($id)
            ;
        }
        else { return;}

            $form = $this->get('form.factory')->create(StagiaireType::Class, $stagiaire);
        
        if ($request->isMethod('POST')) { 
          $form->handleRequest($request);

          if ($form->isValid()) {...

该错误发生在$form->handleRequest($request); 我正在搜索几天的行中,但我没有找到解决方案。有没有人想帮忙?

标签: symfonydoctrineentitysymfony-forms

解决方案


您需要更改函数以接受企业对象而不是 id:

public function getEntreprise(): ?Entreprise
{
    return $this->entreprise;
}

public function setEntreprise(Entreprise $entreprise): self
{
    $this->entreprise = $entreprise;

    return $this;
}

你必须添加use App\Entity\Entreprise;到 Stagiaire 类。


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