r - R - 在城市地图上拟合网格并将数据输入到网格方块中
问题描述
我正在尝试像这样在圣何塞上放置一个网格:
您可以使用以下代码直观地制作网格:
ca_cities = tigris::places(state = "CA") #using tigris package to get shape file of all CA cities
sj = ca_cities[ca_cities$NAME == "San Jose",] #specifying to San Jose
UTM_ZONE = "10" #the UTM zone for San Jose, will be used to convert the proj4string of sj into UTM
main_sj = sj@polygons[[1]]@Polygons[[5]] #the portion of the shape file I focus on. This is the boundary of san jose
#converting the main_sj polygon into a spatialpolygondataframe using the sp package
tst_ps = sp::Polygons(list(main_sj), 1)
tst_sps = sp::SpatialPolygons(list(tst_ps))
proj4string(tst_sps) = proj4string(sj)
df = data.frame(f = 99.9)
tst_spdf = sp::SpatialPolygonsDataFrame(tst_sps, data = df)
#transforming the proj4string and declaring the finished map as "map"
map = sp::spTransform(tst_sps, CRS(paste0("+proj=utm +zone=",UTM_ZONE," ellps=WGS84")))
#designates the number of horizontal and vertical lines of the grid
NUM_LINES_VERT = 25
NUM_LINES_HORZ = 25
#getting bounding box of map
bbox = map@bbox
#Marking the x and y coordinates for each of the grid lines.
x_spots = seq(bbox[1,1], bbox[1,2], length.out = NUM_LINES_HORZ)
y_spots = seq(bbox[2,1], bbox[2,2], length.out = NUM_LINES_VERT)
#creating the coordinates for the lines. top and bottom connect to each other. left and right connect to each other
top_vert_line_coords = expand.grid(x = x_spots, y = y_spots[1])
bottom_vert_line_coords = expand.grid(x = x_spots, y = y_spots[length(y_spots)])
left_horz_line_coords = expand.grid(x = x_spots[1], y = y_spots)
right_horz_line_coords = expand.grid(x = x_spots[length(x_spots)], y = y_spots)
#creating vertical lines and adding them all to a list
vert_line_list = list()
for(n in 1 : nrow(top_vert_line_coords)){
vert_line_list[[n]] = sp::Line(rbind(top_vert_line_coords[n,], bottom_vert_line_coords[n,]))
}
vert_lines = sp::Lines(vert_line_list, ID = "vert") #creating Lines object of the vertical lines
#creating horizontal lines and adding them all to a list
horz_line_list = list()
for(n in 1 : nrow(top_vert_line_coords)){
horz_line_list[[n]] = sp::Line(rbind(left_horz_line_coords[n,], right_horz_line_coords[n,]))
}
horz_lines = sp::Lines(horz_line_list, ID = "horz") #creating Lines object of the horizontal lines
all_lines = sp::Lines(c(horz_line_list, vert_line_list), ID = 1) #combining horizontal and vertical lines into a single grid format
grid_lines = sp::SpatialLines(list(all_lines)) #converting the lines object into a Spatial Lines object
proj4string(grid_lines) = proj4string(map) #ensuring the projections are the same between the map and the grid lines.
trimmed_grid = intersect(grid_lines, map) #grid that shapes to the san jose map
plot(map) #plotting the map of San Jose
lines(trimmed_grid) #plotting the grid
但是,我正在努力将每个网格“正方形”(一些网格块不是正方形,因为它们适合圣何塞地图的形状)变成我可以输入数据的 bin。换句话说,如果每个网格“正方形”的编号为 1:n,那么我可以制作这样的数据框:
grid_id num_assaults num_thefts
1 1 100 89
2 2 55 456
3 3 12 1321
4 4 48 498
5 5 66 6
并用数据填充每个网格“正方形”,每个犯罪事件的点位置,希望使用包中的over()
功能sp
。
我已经尝试解决这个问题好几个星期了,但我无法弄清楚。我一直在寻找一个简单的解决方案,但我似乎找不到它。任何帮助,将不胜感激。
解决方案
此外,这是一个基于 sf 和 tidyverse 的解决方案:
使用 sf,您可以使用该st_make_grid()
功能制作一个正方形网格。在这里,我将在圣何塞的边界框上创建一个 2 公里的网格,然后将其与圣何塞的边界相交。请注意,我正在投影到 UTM 区域 10N,因此我可以以米为单位指定网格大小。
library(tigris)
library(tidyverse)
library(sf)
options(tigris_class = "sf", tigris_use_cache = TRUE)
set.seed(1234)
sj <- places("CA", cb = TRUE) %>%
filter(NAME == "San Jose") %>%
st_transform(26910)
g <- sj %>%
st_make_grid(cellsize = 2000) %>%
st_intersection(sj) %>%
st_cast("MULTIPOLYGON") %>%
st_sf() %>%
mutate(id = row_number())
接下来,我们可以生成一些随机犯罪数据st_sample()
并绘制它以查看我们正在处理的内容。
thefts <- st_sample(sj, size = 500) %>%
st_sf()
assaults <- st_sample(sj, size = 200) %>%
st_sf()
plot(g$geometry)
plot(thefts, add = TRUE, col = "red")
然后犯罪数据可以在空间上加入到网格中st_join()
。我们可以绘图来检查我们的结果。
theft_grid <- g %>%
st_join(thefts) %>%
group_by(id) %>%
summarize(num_thefts = n())
plot(theft_grid["num_thefts"])
然后我们可以对攻击数据执行相同的操作,然后将两个数据集连接在一起以获得所需的结果。如果您有大量犯罪数据集,则可以修改这些数据集以在purrr::map()
.
assault_grid <- g %>%
st_join(assaults) %>%
group_by(id) %>%
summarize(num_assaults = n())
st_geometry(assault_grid) <- NULL
crime_data <- left_join(theft_grid, assault_grid, by = "id")
crime_data
Simple feature collection with 190 features and 3 fields
geometry type: GEOMETRY
dimension: XY
bbox: xmin: 584412 ymin: 4109499 xmax: 625213.2 ymax: 4147443
epsg (SRID): 26910
proj4string: +proj=utm +zone=10 +ellps=GRS80 +towgs84=0,0,0,0,0,0,0 +units=m +no_defs
# A tibble: 190 x 4
id num_thefts num_assaults geometry
<int> <int> <int> <GEOMETRY [m]>
1 1 2 1 POLYGON ((607150.3 4111499, 608412 4111499, 608412 4109738,…
2 2 4 1 POLYGON ((608412 4109738, 608412 4111499, 609237.8 4111499,…
3 3 3 1 POLYGON ((608412 4113454, 608412 4111499, 607150.3 4111499,…
4 4 2 2 POLYGON ((609237.8 4111499, 608412 4111499, 608412 4113454,…
5 5 1 1 MULTIPOLYGON (((610412 4112522, 610412 4112804, 610597 4112…
6 6 1 1 POLYGON ((616205.4 4113499, 616412 4113499, 616412 4113309,…
7 7 1 1 MULTIPOLYGON (((617467.1 4113499, 618107.9 4113499, 617697.…
8 8 2 1 POLYGON ((605206.8 4115499, 606412 4115499, 606412 4114617,…
9 9 5 1 POLYGON ((606412 4114617, 606412 4115499, 608078.2 4115499,…
10 10 1 1 POLYGON ((609242.7 4115499, 610412 4115499, 610412 4113499,…
# ... with 180 more rows
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