python - AttributeError：“dict”对象没有属性“append”

Question

Can someone please tell me what basic thing I am missing here.

Type: <class 'list'>
Value : ['09,10,11,12,13,14,15']

for datapoint in value:
    y.append(datetime.fromtimestamp(datapoint).strftime('%I%P').lstrip('0').upper())

I want value of y should be like this-[9PM,10PM,11PM,12PM,1PM,2PM,3PM]

如果我使用上述函数，我不确定为什么它没有转换为我想要的值。有人可以建议我在这里缺少什么以及为什么会出现此错误->“AttributeError：'dict'对象没有属性'append'”

标签： python

Answer 1

您有一个包含一个字符串的 1 元素列表：您datapoint是整个字符串，而不是它的一部分。您需要拆分并迭代拆分的值：

from datetime import datetime

y = [] # use list to use append, see dict approach below

data = '09,10,11,12,13,14,15'.split(",") #split into ["09","10",...,"15"]

for dp in data: # "09" then "10" then "11" etc.
    y.append(datetime.strptime(dp,"%H").strftime('%I%P').strip("0").upper())

print(y)

输出：

['9AM', '10AM', '11AM', '12PM', '1PM', '2PM', '3PM']

要添加它，您需要使用字典update((key,value)-iterable)或d[key]=value：

d = {}
for time in y:
    d["Time "+time] = time

# or

d.update(  ((t,t) for t in y) ) # doesnt make much sense to have identical key/values

# d[]=... - Output
{'Time 9AM': '9AM', 'Time 12PM': '12PM', 'Time 3PM': '3PM', 
 'Time 11AM': '11AM', 'Time 2PM': '2PM', 'Time 10AM': '10AM', 
 'Time 1PM': '1PM'}

# update - Output 
{'12PM': '12PM', '1PM': '1PM', '11AM': '11AM', '9AM': '9AM', 
 '10AM': '10AM', '3PM': '3PM', '2PM': '2PM'}