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sql - 计算一列中不同条目之间的距离

问题描述

我的表中有这种列：

Table A:

geom_etrs(geometry)
"0101000020E8640000FE2EAF0B3C981C414E499E34DFE65441"
"0101000020E864..."
"0101000020E875..."
"0101000020E867..."

如何计算每个条目之间的距离（它们已经定义为POINT）？

我想创建一个新列，其中显示 1 和 2 之间的距离，然后是 2 和 3 之间的距离，然后是 3 和 4 之间的距离，依此类推。

标签： sqlpostgresqldistancepoint

解决方案

    select st_distance(point, lead(point,1) over (partition by rn)) 
 from ( select point, row_number() over (partition by id) as rn
 from table_1)t;


    gis=# \d users
     user_id | bigint    |  
     geog    | geography | 

select st_astext(geog), st_astext(lead(geog,1) over (partition by rn)) from ( select geog, row_number() over (partition by user_id) as rn from users limit 10)t;
                 st_astext                 |                 st_astext                 
-------------------------------------------+-------------------------------------------
 POINT(-70.0777937636872 41.6670617084209) | POINT(-70.0783833464664 41.6675384387944)
 POINT(-70.0783833464664 41.6675384387944) | POINT(-70.0793901822679 41.667476122803)
 POINT(-70.0793901822679 41.667476122803)  | POINT(-70.0787530494335 41.6671461707966)
 POINT(-70.0787530494335 41.6671461707966) | POINT(-70.07908017161 41.6663672501228)
 POINT(-70.07908017161 41.6663672501228)   | POINT(-70.0795407352778 41.6669886861798)
 POINT(-70.0795407352778 41.6669886861798) | POINT(-70.0798881265976 41.6663775240468)
 POINT(-70.0798881265976 41.6663775240468) | POINT(-70.0781470955597 41.6667824284963)
 POINT(-70.0781470955597 41.6667824284963) | POINT(-70.0790447962989 41.6675773546665)
 POINT(-70.0790447962989 41.6675773546665) | POINT(-70.0778760883834 41.6675017901701)
 POINT(-70.0778760883834 41.6675017901701) |

 gis=# select st_distance(geog, lead(geog,1) over (partition by rn)) from ( select geog, row_number() over (partition by user_id) as rn from users limit 10)t;
 st_distance  
--------------
  72.21147623
  84.13511302
  64.48606246
  90.70040367
  78.96272466
  73.78817244
 151.81026032
 115.69092832
  97.69189128

这应该适合你

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