java - 如何在 JPAQuery 中使用 INNER JOIN？

问题描述

我确切地说我是 Java 开发者第一年的法国学生。而且我很确定我的问题标题对于我正在尝试做的事情甚至都不正确。那么我希望下面的解释会更清楚！

我正在开发一个小的多模块应用程序：Spring Boot、Spring security、Hibernate、Spring Data、Spring MVC 和 Thymeleaf。

我目前正在研究一种处理多条件请求的方法。我正在使用 Querydsl。

这是该域的相关部分：

母体

@Entity
@Table(name="element")
@Inheritance(strategy = InheritanceType.JOINED)
@Getter
@Setter
@NoArgsConstructor
@ToString
@EqualsAndHashCode
public abstract class Element {

//----------ATTRIBUTES----------

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;
    @NotNull
    @Size(min=4,max=50)
    private String name;
    private LocalDateTime createDate;
    private LocalDateTime updateDate;
    @OneToMany/*(mappedBy = "element")*/
    @JoinColumn(name = "element_id")
    private List< Comment > comments;
//..

子实体

/**
 * Bean used to define a book or a document that contains one or many climbing areas
 */
@Entity
@Table(name="atlas")
@PrimaryKeyJoinColumn(name = "element_id")
@Getter
@Setter
@NoArgsConstructor
@ToString( exclude = {"areas" , "bookingRequests" , "user"})
public class Atlas extends Element {

//----------ATTRIBUTES----------

    @ManyToMany
    @JoinTable(
        name = "areas_in_atlases",
        joinColumns = { @JoinColumn(name = "atlas_id") },
        inverseJoinColumns = { @JoinColumn(name = "area_id") } )
    private List< Area > areas;
    private String scale;
    private String country;
    private String region;
    private String department;
    private boolean available;
    @ManyToOne
    @JoinColumn(name = "user_id")
    private User user;
    @OneToMany(mappedBy = "atlas", cascade = CascadeType.ALL)
    private List<BookingRequest> bookingRequests;
//..



/**
 * Bean used to define an area with one or many climbing crag
 */
@Entity
@Table(name="area")
@PrimaryKeyJoinColumn(name = "element_id")
@Getter
@Setter
@NoArgsConstructor
@ToString
@EqualsAndHashCode( callSuper = true )
public class Area extends Element {

//----------ATTRIBUTES----------

    @ManyToMany(mappedBy = "areas")
    private List< Atlas > atlases;
    private Atlas atlas;
    @OneToMany/*(mappedBy = "area", fetch = FetchType.LAZY)*/
    @JoinColumn(name = "area_id")
    private List< Crag > crags;
    private int approachDuration;
    private String locality;
    @OneToMany/*(mappedBy = "area", fetch = FetchType.LAZY)*/
    @JoinColumn(name = "area_id")
    private List< Parking > parking;
    private String rockType;
//..

我的多标准方法的第一部分正在工作（我猜不是很优雅..）：

@Override
public Page<Atlas> searchAtlasByNameAndCountryAndRegionAndDepartment( int page, int size, String name, String country, String region, String department ){

    QAtlas qAtlas = QAtlas.atlas;

    ArrayList< Predicate > predicates = new ArrayList<>();

    List<Atlas> atlases;

    if( !name.equals( "" ) ){
        predicates.add( qAtlas.name.containsIgnoreCase(name) );
    }
    if( !country.equals( "" ) ){
        predicates.add( qAtlas.country.containsIgnoreCase(country) );
    }
    if( !region.equals( "" ) ){
        predicates.add( qAtlas.region.containsIgnoreCase(region) );
    }
    if( !department.equals( "" ) ){
        predicates.add( qAtlas.department.containsIgnoreCase(department) );
    }

    BooleanBuilder booleanBuilder = new BooleanBuilder();

    for ( Predicate predicate: predicates ) {
        booleanBuilder.and(predicate);
    }

    atlases = ( List< Atlas > ) getDaoFactory().getAtlasRepository().findAll( booleanBuilder );

    long total = ( long ) atlases.size( );

    return new PageImpl(atlases, PageRequest.of( page, size ), total );
}

但我坚持使用仅在 Atlas 中的字段（如 Country）在 Area 中搜索的方法。

    @Override
    public Page< Area > searchAreaByNameAndCountryAndRegionAndDepartment( int page, int size, String name, String country, String region, String department ){

        QAtlas qAtlas = QAtlas.atlas;
        QArea qArea = QArea.area;

        final JPAQueryFactory queryFactory = new JPAQueryFactory(em);


        List<Area> areas = queryFactory.selectFrom(qArea)
                                   .innerJoin(qAtlas)
                                   .where(
                                           qArea.name.containsIgnoreCase(name),
                                           qAtlas.country.containsIgnoreCase(country),
                                           qAtlas.department.containsIgnoreCase(department),
                                           qAtlas.region.containsIgnoreCase(region)
                                   )
                                   .fetch();

        long total = ( long ) areas.size( );

        return new PageImpl(areas, PageRequest.of( page, size ), total );
    }

目前控制台说：

ervlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: Invalid path: 'atlas.areas' [select area
from org.thibaut.wheretoclimb.model.entity.Area area
  inner join atlas.areas as area
where lower(area.name) like ?1 escape '!' and lower(atlas.country) like ?2 escape '!' and lower(atlas.department) like ?1 escape '!' and lower(atlas.region) like ?1 escape '!']] with root cause

org.hibernate.hql.internal.ast.QuerySyntaxException: Invalid path: 'atlas.areas' [select area
from org.thibaut.wheretoclimb.model.entity.Area area
  inner join atlas.areas as area
where lower(area.name) like ?1 escape '!' and lower(atlas.country) like ?2 escape '!' and lower(atlas.department) like ?1 escape '!' and lower(atlas.region) like ?1 escape '!']

有没有人可以帮我解决这个问题？

非常感谢你们的时间！

标签： javaspring-dataquerydslpredicate

java - 如何在 JPAQuery 中使用 INNER JOIN？

问题描述

解决方案

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