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r - 绘制一个数据框列表，每个数据框有 4 个变量

问题描述

data.frame 的片段 data.frames 列表的片段

我的列表如下所示：

> dput(lapply(list1, head))
list(structure(c(NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, 
NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA), .Dim = c(6L, 
4L), .Dimnames = list(NULL, c("FPAR", "gpp", "LAI", "npp"))), 
    structure(c(63L, 83L, 66L, 84L, 92L, 85L, 9976L, 3318L, 9456L, 
    9435L, 9002L, 9395L, 21L, 32L, 18L, 34L, 50L, 36L, 6742L, 
    5228L, 5405L, 5136L, 5387L, 5339L), .Dim = c(6L, 4L), .Dimnames = list(
        NULL, c("FPAR", "gpp", "LAI", "npp"))), structure(c(NA, 
    NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, 
    NA, NA, NA, NA, NA, NA, NA, NA), .Dim = c(6L, 4L), .Dimnames = list(
        NULL, c("FPAR", "gpp", "LAI", "npp"))), structure(c(0L, 
    95L, 0L, 82L, 0L, 82L, 10306L, 10205L, 10306L, 10627L, 10306L, 
    10627L, 0L, 64L, 0L, 31L, 0L, 31L, 6396L, 6340L, 6396L, 6396L, 
    6396L, 6396L), .Dim = c(6L, 4L), .Dimnames = list(NULL, c("FPAR", 
    "gpp", "LAI", "npp"))), structure(c(NA, NA, NA, NA, NA, NA, 
    NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, 
    7331L, NA, NA), .Dim = c(6L, 4L), .Dimnames = list(NULL, 
        c("FPAR", "gpp", "LAI", "npp"))), structure(c(96L, 96L, 
    100L, 88L, 93L, 100L, 12734L, 12215L, 11383L, 11446L, 12672L, 
    11531L, 61L, 61L, 70L, 40L, 58L, 70L, 7807L, 7357L, 7695L, 
    6400L, 6009L, 7735L), .Dim = c(6L, 4L), .Dimnames = list(
        NULL, c("FPAR", "gpp", "LAI", "npp"))), structure(c(95L, 
    95L, 96L, 96L, 96L, 95L, 10829L, 10829L, 9652L, 10321L, 9652L, 
    10829L, 61L, 61L, 62L, 65L, 62L, 61L, 5144L, 5144L, 5188L, 
    5422L, 5188L, 5144L), .Dim = c(6L, 4L), .Dimnames = list(
        NULL, c("FPAR", "gpp", "LAI", "npp"))), structure(c(NA, 
    NA, 87L, 63L, 87L, 87L, NA, NA, 7891L, 7891L, 0L, 7891L, 
    NA, NA, 46L, 19L, 46L, 46L, NA, NA, NA, NA, NA, NA), .Dim = c(6L, 
    4L), .Dimnames = list(NULL, c("FPAR", "gpp", "LAI", "npp"
    ))), structure(c(100L, 100L, 100L, 78L, 100L, 100L, 4011L, 
    4011L, 4112L, 4306L, 3664L, 4112L, 70L, 70L, 70L, 21L, 70L, 
    70L, 2253L, 2425L, 2479L, NA, 2253L, 2253L), .Dim = c(6L, 
    4L), .Dimnames = list(NULL, c("FPAR", "gpp", "LAI", "npp"
    ))), structure(c(83L, 87L, 71L, NA, 0L, 82L, 5627L, 6626L, 
    5862L, NA, 6963L, 5541L, 29L, 37L, 16L, NA, 0L, 28L, 3877L, 
    3695L, 3635L, 1642L, 3692L, 3644L), .Dim = c(6L, 4L), .Dimnames = list(
        NULL, c("FPAR", "gpp", "LAI", "npp"))), structure(c(88L, 
    89L, 61L, NA, 0L, 88L, 6132L, 5636L, 6166L, NA, 6510L, 6502L, 
    49L, 51L, 18L, NA, 0L, 50L, 3413L, 3788L, 3519L, NA, 3463L, 
    3755L), .Dim = c(6L, 4L), .Dimnames = list(NULL, c("FPAR", 
    "gpp", "LAI", "npp"))))

因此，我试图为列表中的 11 个数据帧有效地绘制变量 1 (FPAR) 和变量 2-4 (gpp、LAI、npp) 之间的散点图。我附上了我的清单的一个片段。

到目前为止，这是我想出的，但它不起作用。

library(ggplot2)
scatterplot <- function(yvar){
  ggplot(list1, aes_(x=~age, y=as.name(yvar))) + 
    geom_point() +
    facet_wrap(~dataframe)
}
lapply(list1, scatterplot)

这是我第一次使用列表和 ggplot，所以我有点卡住了..

标签： rlistggplot2lapply

解决方案

这是您可以执行此操作的一种方法。

library(tidyverse)
list1 %>% 
  map(., as_data_frame) %>% 
  bind_rows(., .id = "dataframe") %>%
  gather(., key, value, gpp:npp) %>% 
  mutate(dataframe = factor(dataframe, levels = unique(dataframe))) %>% 
  ggplot(., aes(FPAR, value, col = key)) +
  geom_point() +
  facet_wrap(. ~ dataframe, ncol = 3)

警告：删除了 71 行包含缺失值 (geom_point)。

在此处输入图像描述

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