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javascript - 如何从函数中返回数据

问题描述

我正在尝试解决以下 Kata：

一个 2 位数字，如果将数字相加，则乘以 3，加 45 并反转。

我无法弄清楚如何从我的函数中返回数据，以便以后可以将值分配给 HTML 元素。

这是我的代码。

function daily() {
   for(var j = 10; j < 100; j++) {
       function teaser(num) {
           var x = num;
           var y = x.toString().split("");
           if(y.length == 2) {
               var sum = parseInt(y[0]) + parseInt(y[1]);
               if(sum * 3 == x) {
                   console.log(x + " is equal to 3 times " + sum);
                   var addFortyFive = x + 45;
                   console.log("Adding 45 to " + x + " gives " + addFortyFive);
                   var reversal = parseInt(addFortyFive.toString().split('').reverse().join(''));
                   console.log("'The 2 digit number " + x + ", is 3 times the sum (" + sum + ") of its digits. If 45 is added to " + x + ", the result is " + addFortyFive + ". If the digits are reversed, the number is... " + reversal + ".");
               }
           } else {
               console.log("Not a 2 digit Number!!");
           }
       }
       teaser(j);
   }
}

标签： javascriptreturn

解决方案

根据您的问题，我猜您reversal每天都需要对函数的价值进行循环。

建议您从 for-loop 中取出函数预告片，这将使代码更加简洁易懂，您可以这样做：

function daily() {
   for(var j = 10; j < 100; j++) {
       var teaser = teaser(j);
       // Can now use anything returned from teaser function here
   }
}

function teaser(num) {
     var x = num;
     var y = x.toString().split("");
     if(y.length == 2) {
         var sum = parseInt(y[0]) + parseInt(y[1]);
         if(sum * 3 == x) {
             console.log(x + " is equal to 3 times " + sum);
             var addFortyFive = x + 45;
             console.log("Adding 45 to " + x + " gives " + addFortyFive);
             var reversal = parseInt(addFortyFive.toString().split('').reverse().join(''));
             console.log("'The 2 digit number " + x + ", is 3 times the sum (" + sum + ") of its digits. If 45 is added to " + x + ", the result is " + addFortyFive + ". If the digits are reversed, the number is... " + reversal + ".");

             return reversal;
         }
     } else {
         console.log("Not a 2 digit Number!!");
         return false;
     }
 }

如果不想取消功能，那么你可以这样做：

function daily() {
   for(var j = 10; j < 100; j++) {
       function teaser(num) {
           var x = num;
           var y = x.toString().split("");
           if(y.length == 2) {
               var sum = parseInt(y[0]) + parseInt(y[1]);
               if(sum * 3 == x) {
                   console.log(x + " is equal to 3 times " + sum);
                   var addFortyFive = x + 45;
                   console.log("Adding 45 to " + x + " gives " + addFortyFive);
                   var reversal = parseInt(addFortyFive.toString().split('').reverse().join(''));
                   console.log("'The 2 digit number " + x + ", is 3 times the sum (" + sum + ") of its digits. If 45 is added to " + x + ", the result is " + addFortyFive + ". If the digits are reversed, the number is... " + reversal + ".");

                   return reversal;
               }
           } else {
               console.log("Not a 2 digit Number!!");
               return false;
           }
       }

       var teaser = teaser(j);
       // Can now use anything returned from teaser function here
   }
}

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