首页 > 解决方案 > NodeJS Undefined TypeError,我哪里出错了?

问题描述

我正在尝试在 NodeJS 中创建多个用户对象并将它们存储在地图中。这些将由我正在开发的聊天机器人使用。

基本上应该发生的事情是这样的:

  1. 用户第一次与聊天机器人交互时,它会触发“FACEBOOK_WELCOME”回发。如果用户存在(即他们以前使用过,可能在另一台设备上),那么他们将开始正常使用聊天机器人,如果用户不存在,他们将需要创建用户配置文件
  2. 如果用户存在,则后续交互使用现有的用户配置文件,从地图对象读取或从数据库读取然后存储在地图对象中。

我的用户代码如下所示:

'use strict';
const self = module.exports = {

    loadedUsers: new Map(),

    add: function(senderID, data) {
        // Code to load an existing user from the database
        loadedUsers.set(senderID, new User(data.userID, data.gender, data.age));
    },

    addNewUser: function(senderID) {
        // Code to create a blank user object in order to start creating user profile
        loadedUsers.set(senderID, new User());
    },

    User: function(userID, gender, age) {
        if (typeof userID === 'undefined' && typeof gender === 'undefined' 
        && typeof age === 'undefined') {
            this.userID = userID;
            this.gender = gender;
            this.age = age;
        } else {
            this.userID = undefined;
            this.gender = undefined;
            this.age = undefined;
        }
    },
};

当我想创建一个全新的空白用户时,我只需调用该addNewUser(senderID)函数。从理论上讲,这应该在loadedUsers() 映射中添加一个空白用户。但事实并非如此。相反,我收到此错误:

Nov 09 15:16:20 weightmentor app/web.1: /app/app_modules/handler.js:255 
Nov 09 15:16:20 weightmentor app/web.1: user.addNewUser(senderID); 
Nov 09 15:16:20 weightmentor app/web.1:      ^ 
Nov 09 15:16:20 weightmentor app/web.1: TypeError: Cannot read property 'addNewUser' 
of undefined 
Nov 09 15:16:20 weightmentor app/web.1:     at Timeout._onTimeout 
    (/app/app_modules/handler.js:255:34) 
Nov 09 15:16:20 weightmentor app/web.1:     at ontimeout (timers.js:436:11) 
Nov 09 15:16:20 weightmentor app/web.1:     at tryOnTimeout 
(timers.js:300:5) 
Nov 09 15:16:20 weightmentor app/web.1:     at listOnTimeout 
(timers.js:263:5) 
Nov 09 15:16:20 weightmentor app/web.1:     at Timer.processTimers 
(timers.js:223:10)

我不确定为什么会发生此错误。有些东西是未定义的,但问题是,什么?

该函数调用如下:

                common.getFBUser(senderID, function(name) {
                    greetingText = strings.initialGreeting.replace("%USER", name);
                    delay = common.setDelay(greetingText);
                    messaging.sendTextMessage(senderID, greetingText);
                    setTimeout(function() {
                        // Pause before starting user profile creation
                        user.addNewUser(senderID);
                        user.setLoadedUserFirstName(senderID, name);
                        dialogflow.sendRequest(session.getIDs(), senderID, strings.createUser);
                    }, delay);
                });

请注意,common.getFBUser仅使用 Graph.API 从 Facebook 个人资料中获取用户的名字。

标签: node.jsobject

解决方案


我想通了。调用函数的代码部分addNewUser(senderID)如下所示:

        getUser(senderID, function(result) {
            if (common.isDefined(result)) {
                // If a user has been returned from the database, add to the usermap.
                user.add(senderID, result);
                // Once user is added, welcome the user
                greetUser(senderID);
            } else {
                // User has not been returned from the database, this is a new user, so create a user profile
                common.getFBUser(senderID, function(name) {
                    greetingText = strings.initialGreeting.replace("%USER", name);
                    delay = common.setDelay(greetingText);
                    messaging.sendTextMessage(senderID, greetingText);
                    setTimeout(function() {
                        // Pause before starting user profile creation
                        user.addNewUser(senderID, name);
                        dialogflow.sendRequest(session.getIDs(), senderID, strings.createUser);
                    }, delay);
                });
            }
        });

此代码块的第 1 行最初读取getUser(senderID, function(user) {

这意味着当我user.addNewUser(senderID, name)在第 15 行调用时addNewUser(),代码不是调用用户模块中的函数,而是尝试调用在第 1 行的回调中传递的addNewUser(senderID, name)函数user。这当然不存在。当我将第 1 行更改为阅读getUser(senderID, function(result) {时,它工作正常。


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