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python - Python将电话字母翻译成数字问题

问题描述

我知道这个网站之前已经问过这个问题，但我无法理解给出的答案（我还是很新），所以我要再试一次。我的任务是编写代码，该代码采用 10 位电话号码 (XXX-XXX-XXXX) 并将任何字母（即 800-FLO-WERS）转换为数字。我已经为此绞尽脑汁，并且真的可以使用一些帮助/解释。在我正在上课的课程中（使用出色的“从 Python 开始，第 4 版，Tony Gaddis），我不能使用我们尚未涵盖的概念（如字典），但我可以使用列表/元组。我的代码我想出了以下几点：

def main():
    try:
        user_number = str(input('Enter a phone number (XXX-XXX-XXXX): ')).upper()
        converted_number = check_number(user_number)
        print('The phone number is:',converted_number
    except Exception as err:
        print(err)
def check_number(user_number):
    try:
        for char in user_number:
            if char.isalpha():
                result = convert_to_num(char)
                return result
            else:
                return char
        return converted_number
    except Exception as err:
        print(err)
def convert_to_num(char):
    if char in ['A','B','C']:
        char = 2
    elif char in ['D','E','F']:
        char = 3
    elif char in ['G','H','I']:
        char = 4
    elif char in ['J','K','L']:
        char = 5
    elif char in ['M','N','O']:
        char = 6
    elif char in ['P','Q','R','S']:
        char = 7
    elif char in ['T','U','V']:
        char = 8
    elif char in ['W','X','Y','Z']:
        char = 9
    return char
main()

显然，我不确定如何存储转换后的字母到数字（考虑通过索引来完成，但也不能完全做到这一点）。我不是在寻找任何人为我做我的工作，但我做错了什么的详细解释会很可爱。

标签： pythonpython-3.x

解决方案

的目的return是返回调用它的函数。这里因为return在循环内。它将在第一次迭代中退出该函数。

for char in user_number:
     if char.isalpha():
           result = convert_to_num(char)
           return result
     else:
           return char
     return converted_number

只需使用列表来存储转换后的值，然后使用该join()方法在循环后返回它们。

def main():
    try:
        user_number = str(input('Enter a phone number (XXX-XXX-XXXX): ')).upper()
        converted_number = check_number(user_number)
        print('The phone number is:',converted_number)
    except Exception as err:
        print(err)

def check_number(user_number):
    try:
        r = []
        for char in user_number:
            if char.isalpha():
                result = convert_to_num(char)
                r.append(str(result))
            else:
                r.append(char)
        return "".join(r)
    except Exception as err:
        print(err)

def convert_to_num(char):
    if char in ['A','B','C']:
        char = 2
    elif char in ['D','E','F']:
        char = 3
    elif char in ['G','H','I']:
        char = 4
    elif char in ['J','K','L']:
        char = 5
    elif char in ['M','N','O']:
        char = 6
    elif char in ['P','Q','R','S']:
        char = 7
    elif char in ['T','U','V']:
        char = 8
    elif char in ['W','X','Y','Z']:
        char = 9
    return char
main()

如果你不能使用join()

def check_number(user_number):
    try:
        r = ''
        for char in user_number:
            if char.isalpha():
                result = convert_to_num(char)
                r += str(result)
            else:
                r += char
        return r
    except Exception as err:
        print(err)

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