jquery - JQuery 提交按钮不起作用 Laravel

Question

我正在尽一切努力使我的网页更流畅。问题是，我试图提交一个 JQuery，现在，按下该按钮时不会做任何事情。

这是我的代码：

The form:

<form id="myForm">
    <div class="author-thumb">
        <img src="{{ Auth::user()->getFirstMediaUrl('pps') ? Auth::user()->getFirstMediaUrl('pps')  : '/img/ava_10.jpg' }}" width="36" height="36" alt="author">
    </div>
    <div class="form-group with-icon label-floating is-empty">
        <label class="control-label">Share what you are thinking here...</label>
        <textarea class="form-control" name="content" id="content" required></textarea>
    </div>
    <div class="add-options-message">
        <a href="#" class="options-message" data-toggle="tooltip" data-placement="top"   data-original-title="ADD PHOTOS">
            <svg class="olymp-camera-icon" data-toggle="modal" data-target="#update-header-photo"><use xlink:href="icons/icons.svg#olymp-camera-icon"></use></svg>
        </a>
        <button class="btn btn-primary btn-md-2" id="ajaxSubmit">Post</button>
    </div>
</form>

The controller:

public function store(Request $request)
{
    $post = new Post();
    $post->user_id = Auth::user()->id;
    $post->username = Auth::user()->username;
    $post->author = Auth::user()->name;
    $post->content = $request->content;
    $post->save();
    return response()->json(['success'=>'Data is successfully added']);
}

The route:

Route::post('/post', [

'uses' => 'PostController@store',

]);

The JQuery:

<script type="text/javascript">

jQuery(document).ready(function(){
        jQuery('#ajaxSubmit').click(function(e){
           e.preventDefault();
           $.ajaxSetup({
              headers: {
                  'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')
              }
          });
           jQuery.ajax({
              url: "{{ url('/post') }}",
              method: 'post',
              data: {
                 content: jQuery('#content').val()
              },
              success: function(result){
                 console.log(result);
              }});
           });
        });

</script>

有人可以帮我吗？请向我解释代码的哪一部分是错误的，以及我可以做些什么来避免再次犯同样的错误。在此先感谢您的时间。

标签： jquerylaravel

Answer 1

解决方案如下：

<script type="text/javascript">

jQuery(document).ready(function(){
        jQuery('#ajaxSubmit').click(function(e){
           $.ajaxSetup({
              headers: {
                  'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')
              }
          });
           jQuery.ajax({
              url: "{{ url('/post') }}",
              method: 'post',
              data: {
                 _token: '{{csrf_token()}}', <-- ADD THIS LINE!
                 content: jQuery('#content').val()
              },
              success: function(result){
                 console.log(result);
              }});
           });
        });

</script>