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首页 > 解决方案 > WPF - Prism 7.1 - 导航 - 掌握选项卡控件 - 模态/对话框窗口

c# - WPF - Prism 7.1 - 导航 - 掌握选项卡控件 - 模态/对话框窗口

问题描述

我正在使用 Prism 7.1 导航框架 (WPF) 来使用以下配置弹出一个对话框窗口。这是成功的。但是，我希望此弹出窗口具有可以在其中来回导航的选项卡。当我单击弹出框上的按钮以尝试在其中显示 ViewA 时，没有任何反应。通过设置断点，我看到导航路径被命中，并且正在显示正确的视图名称。请参阅 PopUpWindow.cs。但是，当它解析视图时，视图不会显示。更糟糕的是，没有抛出错误！我很困惑为什么会发生这种情况。

假设我的命名空间是正确的，我做错了什么？

PrismApplication.cs

protected override void RegisterTypes(IContainerRegistry containerRegistry)
{
    containerRegistry.RegisterForNavigation<ViewA>();
}

//Have tried register type, register type for navigation, etc etc.

MainWindowViewModel.xaml

<Window 
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:i="http://schemas.microsoft.com/expression/2010/interactivity"
        xmlns:prism="http://prismlibrary.com/"
        prism:ViewModelLocator.AutoWireViewModel="True"
        Height="350" Width="525">
    <i:Interaction.Triggers>
        <prism:InteractionRequestTrigger SourceObject="{Binding NotificationRequest}">
            <prism:PopupWindowAction IsModal="True" CenterOverAssociatedObject="True" />
        </prism:InteractionRequestTrigger>
    </i:Interaction.Triggers>
    <StackPanel>
        <Button Margin="5" Content="Raise Default Notification" Command="{Binding NotificationCommand}" />
    </StackPanel>

MainWindowViewModel.cs

public MainWindowViewModel
{
    public InteractionRequest<INotification> NotificationRequest { get; set; }
    public DelegateCommand NotificationCommand { get; set; }

    public MainWindowViewModel()
    {
        NotificationRequest = new InteractionRequest<INotification>();
        NotificationCommand = new DelegateCommand(RaiseNotification);
    }

    void RaiseNotification()
    {
        NotificationRequest.Raise(new PopupWindow());
    }
}

弹出窗口.xaml

<UserControl 
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:prism="http://prismlibrary.com/"
        prism:ViewModelLocator.AutoWireViewModel="True"
        Height="350" Width="525">
    <DockPanel LastChildFill="True">
        <StackPanel Orientation="Horizontal" DockPanel.Dock="Top" Margin="5" >
            <Button Command="{Binding NavigateCommand}" CommandParameter="ViewA" Margin="5">Navigate to View A</Button> 
        </StackPanel>
        <ContentControl prism:RegionManager.RegionName="ContentRegion" Margin="5"  />
    </DockPanel>
</UserControl>

弹出窗口.cs

public class PopupWindowViewModel
{
    private readonly IRegionManager _regionManager;

    public DelegateCommand<string> NavigateCommand { get; private set; }

    public PopupWindowViewModel(IRegionManager regionManager)
    {
        _regionManager = regionManager;

        NavigateCommand = new DelegateCommand<string>(Navigate);
    }

    private void Navigate(string navigatePath)
    {
        if (navigatePath != null)
            _regionManager.RequestNavigate("ContentRegion", navigatePath); 

        //During debugging, this correctly shows navigatePath as "ViewA"
    }
}

ViewA.xaml

<UserControl 
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             xmlns:prism="http://prismlibrary.com/"             
             prism:ViewModelLocator.AutoWireViewModel="True">
    <Grid>
        <TextBlock Text="ViewA" FontSize="48" HorizontalAlignment="Center" VerticalAlignment="Center" />
    </Grid>
</UserControl>

标签： c#wpfxamlnavigationprism

解决方案

也许只是没有找到你的观点。第二个参数不应该是 url 而不是字符串吗？从这里： https ://prismlibrary.github.io/docs/wpf/Navigation.html

    IRegionManager regionManager = ...;
regionManager.RequestNavigate("MainRegion",
                                new Uri("InboxView", UriKind.Relative));

检查您的视图在哪里以及路径应该是什么。我认为你可以证明使用类似的东西：

var testinstance = System.Windows.Application.LoadComponent(testUrl);

https://docs.microsoft.com/en-us/dotnet/api/system.windows.application.loadcomponent?view=netframework-4.7.2

如果您使用的是 MEF，我认为您还需要使用 Export 属性标记 View。

希望您的问题只是您忘记了文件夹或类似的东西。

如果不是，则可能与 regionmanager 未获得对您所在地区的引用有关。

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