首页 > 解决方案 > 在泛型类的静态类中使用泛型类型

问题描述

在一个安静的项目中,我正在尝试使用通用响应。在这个通用响应中,有一个静态 responseBuilder。但是 responseBuilder 中的 build 方法不能接受泛型。代码 :

public class RestResponse<T>{

private int status;

private String message;

private T entity;

/**
 * 
 */
public static class RestResponseBuilder {

    private final RestResponse restResponse;

    public RestResponseBuilder(RestResponse resp) {
        this.restResponse = resp;
    }

    public static RestResponseBuilder ok() {

        return status(HttpServletResponse.SC_OK).msg("ok");
    }

    public static RestResponseBuilder status(int status) {
        final RestResponse resp = new RestResponse();
        resp.setStatus(status);

        return new RestResponseBuilder(resp);
    }

    public RestResponseBuilder msg(String msg) {
        this.restResponse.setMessage(msg);
        return this;
    }

    public RestResponseBuilder entity(Object entity) {
        this.restResponse.setEntity(entity);
        return this;
    }

    public RestResponse build() {

        return restResponse;
    }
}

}

当我这样使用时: RestResponseBuilder.ok().entity(null).build(); 有一个警告:类型安全:RestResponse 类型的表达式需要未经检查的转换才能符合

我的问题是,如何在 RestResponseBuilder 中添加泛型类型以避免此警告?谢谢

标签: javagenericsgeneric-type-argument

解决方案


不要使用原始类型。使您的构建器类也通用,其静态方法也通用:

public class RestResponse<T> {

    private int status;

    private String message;

    private T entity;

    /**
     *
     */
    public static class RestResponseBuilder<T> {

        private final RestResponse<T> restResponse;

        public RestResponseBuilder(RestResponse<T> resp) {
            this.restResponse = resp;
        }

        public static <T> RestResponseBuilder<T> ok() {

            return RestResponseBuilder.<T>status(200).msg("ok");
        }

        public static <T> RestResponseBuilder<T> status(int status) {
            final RestResponse<T> resp = new RestResponse<T>();
            resp.status = status;

            return new RestResponseBuilder<T>(resp);
        }

        public RestResponseBuilder<T> msg(String msg) {
            this.restResponse.message = msg;
            return this;
        }

        public RestResponseBuilder<T> entity(T entity) {
            this.restResponse.entity = entity;
            return this;
        }

        public RestResponse<T> build() {

            return restResponse;
        }
    }

}

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