python - 在数字列表中找到最接近的记录速度 [python]

Question

我需要知道如何遍历列表并找到最接近限速的速度。所以几乎每次都遍历速度列表，查看差异。

到目前为止我所拥有的：

def find_nearest_speed(recorded_speeds, speed_limit):
"""Finds the closest recorded speed when compared to the speed limit."""
closest = abs(speed_data[0] - speed_limit)
for current_element in speed_data:
    speed_difference = abs(current_element - speed_limit)
    if speed_difference < abs(closest - speed_limit):
        closest = current_element
        return closest

max_speed = 30 
speed_data = [24, 25, 27, 28, 31, 35]           
closest_speed = (find_nearest_speed(speed_data, max_speed))
print("The closest recorded speed was {} Km/h.".format(closest_speed))

我得到什么：

 The closest recorded speed was 24 Km/h.

我应该得到什么：

 The closest recorded speed was 31 Km/h.

标签： pythonfor-loop

Answer 1

你可以使用min：

max_speed = 30
speed_data = [24, 25, 27, 28, 31, 35]
closest_speed = min(speed_data, key=lambda x: abs(x - max_speed))
print("The closest recorded speed was {} Km/h.".format(closest_speed))

输出

The closest recorded speed was 31 Km/h.