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swift4.2 - 如何在 swift 4.2 中屏蔽字符串

问题描述

我想在一个字符串中制作一个面具。

let unmasked = "12345678900"
//string masked = "123.456.789-00"

这是巴西 CPF 格式，我在 Stack Overflow BR 中一无所获

标签： swift4.2

解决方案

我找到了一个使用字符数组和 array.insert 在定义的索引中插入掩码的解决方案

葡萄牙语：Eu encontrei uma solução usando um array de caracteres ea função array.insert que permite inserir qualquer string em um determinado index da matriz。

let cpf = "12345678900"
var characters = Array(cpf) //making a character array (criando um array de caracteres)

characters.insert(".", at: 3) //inserting "." in index 3 (inserindo "." no index 3) 
//character = ["1","2","3",".","4","5","6","7","8","9","0","0"]

characters.insert(".", at: 7) // inserting "." in index 7 (inserindo "." no index 7)
//character = ["1","2","3",".","4","5","6",".","7","8","9","0","0"]

characters.insert("-", at: 11)// inserting "." in index 11 (inserindo "." no index 11)
//character = ["1","2","3",".","4","5","6",".","7","8","9","-","0","0"]

let masked = String(characters) //convert character to string
pint("cpf masked: ",masked)
//the masked will show: 123.456.789-00 (a mascara irá mostrar: 123.456.789-00)

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