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c - 打印菜单功能选择后继续打印

问题描述

我应该制作一个程序，它是一个使用函数来提供结果的计算器。我把它记下来了，一切正常，但在幽默的一切中，我的打印功能有点小问题；出于某种原因，每当程序打印解决方案时，我似乎都无法理解，它还会打印第一个选择，即 add(num1, num2) 并且我一生都无法弄清楚原因。任何投入将不胜感激！谢谢！这是我的代码：

//Function to Add
int add (int a, int b);
//Function to Substract
int sub (int a, int b);
//Function to Multiply
int mul (int a, int b);
//Function to Divide
int div (int a, int b);
//Function to get remainder
int rem (int a, int b);
//Function to print menu
int printmenu();

//Begin main
int main()
{
    //Initialize Variables
    int num1=0;
    int num2=0;
    unsigned int selection =0;
    
    //Loop
    while ((selection=printmenu()) != 6)
    {
        switch (selection)
        {
        //Addition Case
        case 1: 
            printf("Enter two numbers: ");
            scanf("%d %d", &num1 , &num2 );
            printf("%d added to %d is %d",num1,num2,add(num1,num2));
            break;
        case 2:
            printf("Enter two numbers: ");
            scanf("%d %d", &num1 , &num2 );
            printf("%d substracted to %d is %d",num1,num2,sub(num1,num2));
            break;
        case 3:
            printf("Enter two numbers: ");
            scanf("%d %d", &num1 , &num2 );
            printf("%d multiplied to %d is %d",num1,num2,mul(num1,num2));
            break;  
        case 4:
            printf("Enter two numbers: ");
            scanf("%d %d", &num1 , &num2 );
            printf("%d divided to %d is %d",num1,num2,div(num1,num2));
            break;
        case 5:
            printf("Enter two numbers: ");
            scanf("%d %d", &num1 , &num2 );
            printf("%d divided to %d has a remainder of %d",num1,num2,rem(num1,num2));
            break;
        case 6:
            return 0;
        default:
            printf("That is not a valid choice.");
            break;
        }//End switch
    }//End while
    
    return 0;   
}//End main


//Function to add
int add (int a, int b)
{
    int total=0;
    total = a + b;
    return total;
}

//Function to substract
int sub (int a, int b)
{ 
    int total=0;
    total = a - b;
    return total;
}

//Function to multiply
int mul (int a, int b)
{
    int total=0;
    total = a * b;
    return total;
}

//Function to Divide
int div (int a, int b)
{
    int total=0;
    total = a / b;
    return total;
}

//Function to get Remainder
int rem (int a, int b)
{
    int total=0;
    total = a % b;
    return total;
}

//Function to Print Menu
int printmenu()
{
    int selection=0;
    //Print menu
    printf("1.Add\n");
    printf("2.Substract\n");
    printf("3.Multiply\n");
    printf("4.Divide\n");
    printf("5.Remainder\n");
    printf("6.Exit\n");
    printf("Selection: ");
    scanf("%d", &selection);
    return selection; 
}

标签： cfunctionswitch-statementprintfselection

解决方案

当您打印操作结果时，您不会在输出末尾包含换行符。因此，当您打印菜单时，菜单的第一行也会打印在同一行上。

\n在每个结果打印语句的末尾添加，例如：

printf("%d added to %d is %d\n",num1,num2,add(num1,num2));

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