android - 我无法运行 Espresso 测试
问题描述
我对浓缩咖啡测试有疑问。当测试开始时,我总是得到这个:开始运行测试测试运行失败:
由于“java.lang.ClassNotFoundException”,检测运行失败
空的测试套件。
我已经重新启动、清理、重建项目并且仍然相同。有谁知道出了什么问题?
摇篮:
apply plugin: 'com.android.application'
android {
compileSdkVersion 28
defaultConfig {
applicationId "com.example.daniellachacz.taskmvvm"
minSdkVersion 22
targetSdkVersion 28
versionCode 1
versionName "1.0"
testInstrumentationRunner "android.support.test.runner.AndroidJUnitRunner"
testInstrumentationRunner "com.android.test.runner.MultiDexTestRunner"
multiDexEnabled true
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
}
}
dataBinding {
enabled = true
}
compileOptions {
sourceCompatibility = '1.8'
targetCompatibility = '1.8'
}
}
dependencies {
implementation fileTree(dir: 'libs', include: ['*.jar'])
implementation 'com.android.support:appcompat-v7:28.0.0'
implementation 'com.android.support.constraint:constraint-layout:1.1.3'
testImplementation 'junit:junit:4.12'
implementation 'com.android.support:multidex:1.0.3'
//Livedata
implementation 'android.arch.lifecycle:livedata:1.1.1'
implementation "android.arch.lifecycle:extensions:1.1.1"
//Room
implementation "android.arch.persistence.room:runtime:1.1.1"
annotationProcessor "android.arch.persistence.room:compiler:1.1.1"
implementation "android.arch.persistence.room:rxjava2:1.1.1"
//FloatingActionButton
implementation 'com.melnykov:floatingactionbutton:1.3.0'
//RecyclerView
implementation 'com.android.support:recyclerview-v7:28.0.0'
implementation 'com.android.support:cardview-v7:28.0.0'
//Espresso
androidTestImplementation 'androidx.test.espresso:espresso-core:3.1.0'
androidTestImplementation 'androidx.test:runner:1.1.0'
androidTestImplementation 'androidx.test:rules:1.1.0'
}
测试类:
@RunWith(AndroidJUnit4.class)
public class MainScreenTest {
@Rule
public ActivityTestRule<MainActivity> mainActivityActivityTestRule =
new ActivityTestRule<>(MainActivity.class);
@Test
public void floatingActionButton() {
onView(withId(R.id.floating_action_button))
.check(matches(isDisplayed()));
}
解决方案
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