python - csv阅读器输出额外的空白项

问题描述

我有一个输入 csv，其中包含可变数量的列，我试图将其拉入列表。我的测试是解析输入 csv 并在 csv 列周围创建一个包含额外元素的列表。我想看到的是一个只包含 csv 元素的列表，而且我也得到了空的引用元素。我需要一些帮助来了解我缺少的 csv 阅读器的哪些选项。

示例输出：

$ python cond.py
opening conditions file  conditions.lst
parser  0  input line:
"string1:", "string1b,string1c,"
output list elements:
['string1:']
['', '']
['']
['string1b,string1c,']
[]

parser  1  input line:
"stringa:", "stringb,stringc,"
output list elements:
['stringa:']
['', '']
['']
['stringb,stringc,']
[]

parser  2  input line:
"string3:", "string3next=abc", "string3b","string3c:", "string3d"
output list elements:
['string3:']
['', '']
['']
['string3next=abc']
['', '']
['']
['string3b']
['', '']
['string3c:']
['', '']
['']
['string3d']
[]

输入文件：

$ cat conditions.lst
"string1:", "string1b,string1c,"
"stringa:", "stringb,stringc,"
"string3:", "string3next=abc", "string3b","string3c:", "string3d"

Python cond.py 文件：

$ cat cond.py

from __future__ import print_function
#from csv import reader

import re
import sys
import csv

# variables

conditionsFile = "conditions.lst"
parserConditions = []
numOfParsers = 0


print("opening conditions file ", conditionsFile)
with open(conditionsFile, "r") as cf:
  for line in cf:
    print("parser ", numOfParsers, " input line:")
    print(line.strip())

    r = csv.reader(line, quotechar='"', delimiter=',', quoting=csv.QUOTE_ALL, skipinitialspace=True)
    print("output list elements:")
    for cline in  r:
      print(cline)

    numOfParsers = numOfParsers + 1
    print("")

  print("total number of parsers: ", numOfParsers)

更新：使用@Jean-FrançoisFabre 的帮助我没有解决根本原因，但有一个解决方法 - 我将 csv 元素放入列表中，然后删除空白元素。

for cline in  r:
  conditions.extend(cline)

conditions = filter(None, conditions)
print(conditions)

标签： pythonpython-2.7csv

csv.reader接受一个类似文件的对象而不是字符串......所以它奇怪地迭代一行的字符而不是文件的行。您只需要：

from __future__ import print_function
import csv

with open('conditions.lst','rb') as cf:
    r = csv.reader(cf,skipinitialspace=True)
    for line in r:
        print(line)

输出：

['string1:', 'string1b,string1c,']
['stringa:', 'stringb,stringc,']
['string3:', 'string3next=abc', 'string3b', 'string3c:', 'string3d']

python - csv阅读器输出额外的空白项

问题描述

解决方案

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