java - Java猜数字游戏（不带扫描仪）

Question

所以它就像一个基本的服务器/客户端游戏，但数字必须由客户端生成，并且客户端必须进行逻辑猜测，例如，如果服务器说“输入较小的数字”到 5，“输入一个更大的数字”到0，客户的猜测必须在0到5之间。这部分怎么办？

标签： javaserverclient

Answer 1

如果它是您正在努力解决的客户“猜测”部分，最简单的实现是简单地在您不会“太高”的最小数字和您知道“太低”的最大数字之间保持中间，例如：

public class NumberGuessingClientExample {

public static void main(String[] args) {
    new NumberGuessingClient(new ServerStub()).findNumber();
}

public static class NumberGuessingClient {
    private int min = Integer.MIN_VALUE;
    private int max = Integer.MAX_VALUE;
    private final NumberGuessingServer server;

    public NumberGuessingClient(NumberGuessingServer server) {
        this.server = server;
    }

    public int findNumber() {
        Result result = null;
        int value = nextGuess();
        while ((result = server.makeGuess(value)) != Result.CORRECT) {
            System.out.println(value + " = " + result);
            if (result == Result.TOO_HIGH) {
                max = value - 1;
            } else if (result == Result.TOO_LOW) {
                min = value + 1;
            }
            value = nextGuess();
        }
        System.out.println(value);
        return value;
    }

    private int nextGuess() {
        return (int) ((((long) max - (long) min) / 2) + min);
    }
}

public interface NumberGuessingServer {
    Result makeGuess(int value);
}

public static class ServerStub implements NumberGuessingServer {

    private static final int RESULT = 3;

    public Result makeGuess(int value) {
        if (value > RESULT) {
            return Result.TOO_HIGH;
        }
        if (value < RESULT) {
            return Result.TOO_LOW;
        }
        return Result.CORRECT;
    }

}

public enum Result {
    CORRECT, TOO_HIGH, TOO_LOW
}

}