首页 > 解决方案 > 将数组值从控制器传递到模型以进行插入/更新操作

问题描述

我正在使用 API 收到支付网关的支付交易确认,如下所示。但我无法使用响应并插入数据库。

我的控制器:

$transaction_id= filter_input(INPUT_POST, 'pay_id');
$api = new Api('ID', 'key');   
//getting object of transation
$payment = $api->payment->fetch($transaction_id);
//passing payment details to database
$this->Payment_model->set_payment($transaction_id,true);

$payment数组的当前结构:

pay\Api\Payment Object ( [attributes:protected] => Array ( [id] => pay_BVzDNK3vsp4Owl [entity] => payment [amount] => 35400 [currency] => INR [status] => authorized [order_id] => ) )

我的pay_model.php

  public function set_payment($payment,$first)
  {
      $data = array(
          'id' => $id,
          'entity' => $entity,
          'amount' => $amount,
          'currency' => $currency,
          'status' => $status,
          'order_id' => $order_id,
          'updated_at' => date('Y-m-d H:i:s')
      );
      if ($first == TRUE) {
          //print_r($data);
          //  echo "breakpoint--i am in set user model id 0";
          return $this->db->insert('payments', $data);
      } else {
          //echo "breakpoint--i am in set user model id not 0";
          $this->db->where('id', $id);
          return $this->db->update('payments', $data);
      }
  }

问题:我的 $data 数组总是接收 NULL 值。如何使用我在此处接收的数据并将其传递给模型以进行插入/更新操作。

标签: phpcodeignitercodeigniter-3

解决方案


数组的值$data未在函数范围内定义(它为您提供 NULL 值)。

您有 2 个错误。首先是发送正确的数据来set_payment运行:

$payment = $api->payment->fetch($transaction_id);
$this->Payment_model->set_payment($transaction_id,true);

我认为第二行应该是:

$this->Payment_model->set_payment($payment,true);

作为发送$payment而不是发送$transaction_id

第二个错误是在set_payment函数中使用数据时。创建时$data,您应该将其用作:

'id' => $payment['id'], //and no just $id 
'entity' => $payment['entity'],//and no just $entity as those var not exist in this scope
// and so on...

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