首页 > 解决方案 > 将抓取的数据附加到 JSON 文件

问题描述

我正在尝试从抓取的数据中制作一个 json 文件。但是,基于我的函数 converToJson() 它会一直覆盖上一个条目而不是附加。是因为我没有迭代它吗?例如:下面的 Json 文件每次都会用新数据覆盖第一个条目,而不是附加到它。

[{"Volume": "Volume:\n6,061,086", "Price": "$ 41.88", "Name": "Suncor Energy Inc."}]

def getStockDetails(url, browser):
    
        print(url)
        browser.get(url)
    
        quote_wrapper = browser.find_element_by_css_selector('div.quote-wrapper')
        quote_name = quote_wrapper.find_element_by_class_name(
            "quote-name").find_element_by_tag_name('h2').text
        quote_price = quote_wrapper.find_element_by_class_name("quote-price").text
        quote_volume = quote_wrapper.find_element_by_class_name(
            "quote-volume").text
    
        print("\n")
        print("Quote Name: " + quote_name)
        print("Quote Price: " + quote_price)
        print("Quote Volume: " + quote_volume)
        print("\n")
    
        convertToJson(quote_name,quote_price,quote_volume)
 
  
 def convertToJson(quote_name,quote_price,quote_volume):
        quotesArr = []
        quoteObject = {
            "Name": quote_name,
            "Price": quote_price,
            "Volume": quote_volume
        }
        quotesArr.append(quoteObject)

        with open('trendingQuoteData.json', 'w') as outfile:
            json.dump(quotesArr, outfile)

标签: pythonjsonselenium-webdriverweb-scrapingbeautifulsoup

解决方案


您需要使变量成为quotesArr全局变量,将其放在函数之外并在完成后编写您的 json。

quotesArr = []
def convertToJson(quote_name,quote_price,quote_volume):
    quoteObject = {
        "Name": quote_name,
        "Price": quote_price,
        "Volume": quote_volume
    }
    quotesArr.append(quoteObject)

def trendingBot(url, browser):
    browser.get(url)
    trending = getTrendingQuotes(browser)
    for trend in trending:
        getStockDetails(trend, browser)
    # requests finished, write json to file
    with open('trendingQuoteData.json', 'w') as outfile:
        json.dump(quotesArr, outfile)

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