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python - 将 2 个列表的字符串表示形式转换为列表

问题描述

我想用一个字符串创建一个列表。我的字符串：

[[1544434140,asd,asd,asd]]

如您所见，我的 String 在另一个列表中包含一个列表，如果我想这样做，这绝对是必要的：

[[1544434140,asd,asd,asd][1544434140,asd,asd,asd]]

我已经尝试过：

literal_eval(mystring)

和

eval(mystring)

但两者都从 ast.literal_eval 抛出这样的异常：

Traceback (most recent call last):
  File "/usr/local/lib/python3.6/socketserver.py", line 317, in _handle_request_noblock
    self.process_request(request, client_address)
  File "/usr/local/lib/python3.6/socketserver.py", line 348, in process_request
    self.finish_request(request, client_address)
  File "/usr/local/lib/python3.6/socketserver.py", line 361, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "/usr/local/lib/python3.6/socketserver.py", line 696, in __init__
    self.handle()
  File "/usr/local/lib/python3.6/http/server.py", line 418, in handle
    self.handle_one_request()
  File "/usr/local/lib/python3.6/http/server.py", line 406, in handle_one_request
    method()
  File "/home/dev/requestHandler.py", line 223, in do_GET
    addrequestResult = rh.addRequestToQue(self.path)
  File "/home/dev/requestHandler.py", line 86, in addRequestToQue
    resultOK = self.addToList(request)
  File "/home/dev/requestHandler.py", line 181, in addToList
    doAdd(request, userque, userhistory)
  File "/home/dev/requestHandler.py", line 143, in doAdd
    userque = literal_eval(userque)
  File "/usr/local/lib/python3.6/ast.py", line 85, in literal_eval
    return _convert(node_or_string)
  File "/usr/local/lib/python3.6/ast.py", line 61, in _convert
    return list(map(_convert, node.elts))
  File "/usr/local/lib/python3.6/ast.py", line 61, in _convert
    return list(map(_convert, node.elts))
  File "/usr/local/lib/python3.6/ast.py", line 84, in _convert
    raise ValueError('malformed node or string: ' + repr(node))
ValueError: malformed node or string: <_ast.Name object at 0x7fa6751838d0>

知道如何将带有 2 个封装列表的字符串转换为一个列表吗？

标签： python

解决方案

根据我的假设，如果 asd 不是变量并且在扁平列表中需要“，”。如果有的话让我知道

试试这个格式字符串 eval() 会起作用

mystring = "[[1544434140,'asd','asd','asd'],[1544434140,'asd','asd','asd']]"
print eval(mystring)

Result:[[1544434140, 'asd', 'asd', 'asd'], [1544434140, 'asd', 'asd', 'asd']]

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