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youtube-api - AppleScript 无法获得 api 响应的引用形式

问题描述

我今天早些时候制作了一个 AppleScript，它显示了 Geektools 的 YouTube 订阅者数量，但我希望它更易于人们使用，并试图让它与文件名无关（例如，采用 subcount-PewDiePie.scpt 和输出 PewDiePie 的子计数），并且我已经从文件名中输入名称，但是当我尝试从 api 的响应中取出数字时它给了我错误

工作（原始）的代码

set apiResponse to (do shell script "curl -s 'https://www.googleapis.com/youtube/v3/channels?part=statistics&forUsername=PewDiePie&fields=items%2Fstatistics%2FsubscriberCount&key=AIzaSyAEQGj2ZcDrTU0ZqzteD8eDVJwB9cpmvEo'")

on returnNumbersInString(inputString)
    set s to quoted form of inputString
    do shell script "sed s/[a-zA-Z\\']//g <<< " & s
    set dx to the result
    set numlist to {}
    repeat with i from 1 to count of words in dx
        set this_item to word i of dx
        try
            set this_item to this_item as number
            set the end of numlist to this_item
        end try
    end repeat
end returnNumbersInString

returnNumbersInString(apiResponse)

损坏的可定制代码

set channelName to path to me as text
set oldDelims to AppleScript's text item delimiters
set AppleScript's text item delimiters to {"subcount-"}
set nameFilter to text items of channelName
set channelName to item 2 of nameFilter

set AppleScript's text item delimiters to {"."}
set nameFilter to the text items of channelName
set channelName to item 1 of nameFilter

set curlLink to "https://www.googleapis.com/youtube/v3/channels?part=statistics&forUsername=" & channelName & "&fields=items%2Fstatistics%2FsubscriberCount&key=AIzaSyAEQGj2ZcDrTU0ZqzteD8eDVJwB9cpmvEo"
set curlCommand to "curl -s " & (quoted form of curlLink)

set apiResponse to {do shell script curlCommand}
on returnNumbersInString(inputString)
    set s to quoted form of inputString
    do shell script "sed s/[a-zA-Z\\']//g <<< " & s
    set dx to the result
    set numlist to {}
    repeat with i from 1 to count of words in dx
        set this_item to word i of dx
        try
            set this_item to this_item as number
            set the end of numlist to this_item
        end try
    end repeat
end returnNumbersInString

returnNumbersInString(apiResponse)

每次我做第二个它输出错误

Can’t get quoted form of {"{
 \"items\": [
  {
   \"statistics\": {
    \"subscriberCount\": \"76957805\"
   }
  }
 ]
}"}.

从网站获取信息后立即失败，这没有任何意义，因为除了获取网站链接的方式之外，没有任何代码被更改，谁能帮我解决这个问题

标签： youtube-apiapplescriptyoutube-data-api

解决方案

您已do shell script在此处将命令括在大括号中：

set apiResponse to {do shell script curlCommand}

因此，apiResponse现在是一个包含 JSON 字符串的列表，而不是简单的 JSON 字符串。删除大括号，使该行显示为：

set apiResponse to do shell script curlCommand

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