android - 如何转换完整的字符串 10 + 20 - 25；像文本一样，从 EditText 获得，加倍？

Question

我如何转换包含数学算术运算的"10 + 20 - 25"字符串，我从 EditText 获取字符串，我想转换得到操作的结果。

标签： androidstringandroid-edittextdouble

Answer 1

这是我的代码来解决您的问题：

public class ExecuteHandler {
    private static Character[] OPERATORS = { '/', '*', '+', '-' };

    private static final String REGEXOPERATORS = "[/+,-,/*,//,-]";
    private static final String REGEXDIGITS = "(\\d+)";

    private ArrayList<Character> operators = new ArrayList<>();
    private ArrayList<Integer> digits = new ArrayList<>();

    public String execute(String math) {
        StringBuilder result = new StringBuilder();
        try {
            getDigits(math);
            getOperators(math);
            getNextOperator(operators);

            for (Integer digit : digits) {
                result.append(String.valueOf(digit));
            }
        } catch (ArithmeticException | IndexOutOfBoundsException e) {
            return "ERROR";
        }

        return result.toString().isEmpty() ? "ERROR" : result.toString();
    }

    public void clear() {
        operators.clear();
        digits.clear();
    }

    private void getNextOperator(ArrayList<Character> operators) {
        for (Character op : OPERATORS) {
            for (int i = 0; i < operators.size(); i++) {

                if (operators.get(i) == '/') {
                    operators.remove(i);
                    digits.set(i, (digits.get(i) / digits.get(i + 1)));
                    digits.remove(i + 1);
                    i -= 1;
                }
            }

            for (int i = 0; i < operators.size(); i++) {

                if (operators.get(i) == '*') {
                    operators.remove(i);
                    digits.set(i, (digits.get(i) * digits.get(i + 1)));
                    digits.remove(i + 1);
                    i -= 1;
                }
            }

            for (int i = 0; i < operators.size(); i++) {

                if (operators.get(i) == '+') {
                    operators.remove(i);
                    digits.set(i, (digits.get(i) + digits.get(i + 1)));
                    digits.remove(i + 1);
                    i -= 1;
                }
            }
            for (int i = 0; i < operators.size(); i++) {
                if (operators.get(i) == '-') {
                    operators.remove(i);
                    digits.set(i, (digits.get(i) - digits.get(i + 1)));
                    digits.remove(i + 1);
                    i -= 1;
                }
            }
        }
    }

    private void getDigits(String math) {
        Pattern r = Pattern.compile(REGEXDIGITS);
        Matcher m = r.matcher(math);
        while (m.find()) {
            int t = Integer.parseInt(math.substring(m.start(), m.end()));
            digits.add(t);
        }
    }

    private void getOperators(String math) {
        Pattern r = Pattern.compile(REGEXOPERATORS);
        Matcher m = r.matcher(math);
        while (m.find()) {
            operators.add(math.charAt(m.start()));
        }
    }
}

execute带输入的调用方法string就像"10 + 20 - 25:"，结果将是一串值（如果成功）或ERROR（如果有任何语法错误）。