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scala - Scala如何订阅多个kafka主题

问题描述

我想在scala中将字符串数组/列表转换为util.Collection[String]对象。我尝试了多种方法，但没有成功。

import org.apache.kafka.clients.consumer.KafkaConsumer


object KafkaConsumerApp {

  def main(args: Array[String]): Unit = {

    val prop:Properties = new Properties()
    prop.put("bootstrap.servers","192.168.1.100:9092,192.168.1.141:9092,192.168.1.113:9092,192.168.1.118:9092")
    prop.put("key.deserializer","org.apache.kafka.common.serialization.StringDeserializer")
    prop.put("value.deserializer","org.apache.kafka.common.serialization.StringDeserializer")

    val consumer = new KafkaConsumer(prop)

    val topics = List[String] ("my_topic_partition","my_topic_partition")
    val a = Collections.singletonList(topics)

    consumer.subscribe(a)

  }
}

consumer.subscribe(a) 返回编译时错误

Error:(24, 14) overloaded method value subscribe with alternatives:
  (x$1: java.util.regex.Pattern)Unit <and>
  (x$1: java.util.Collection[String])Unit
 cannot be applied to (java.util.List[List[String]])
    consumer.subscribe(a)

标签： scalaapache-kafkakafka-consumer-api

解决方案

你不需要做一个Singleton List. AList已经是Collection.

val: List[String] topics = List("my_topic_partition","my_topic_partition")
consumer.subscribe(topics)

如果您需要它是Java，只需输入并.asJava使用topics.asJava导入import collection.JavaConverters._

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