android - 我怎样才能解析 JSON 对象？只是一个简单的对象我是新来的

Question

我想在这个上获取字符串值

{"response":"success","Message":"产品创建成功"}

final JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null,
    new Response.Listener<JSONObject>() {
        @Override
        public void onResponse(JSONObject response) {
            try {

                JSONObject JO = response.getJSONObject();
                String respond = JO.getString("response");
                String message = JO.getString("Message");
                Toast.makeText(MainActivity.this, respon + message,Toast.LENGTH_SHORT).show();



            } catch (JSONException e) {
                    e.printStackTrace();
            }
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {

        }
});

标签： androidjsonparsing

Answer 1

您必须在您的try{...}块中编写此代码

String respond = response.getString("response");
String message = response.getString("Message");
Toast.makeText(MainActivity.this, respond + message,Toast.LENGTH_SHORT).show();