javascript - 使用已在多选复选框中选择的数组创建新的移动页面
问题描述
我创建了一个多列表复选框表单,并尝试将选定的值移动到另一个移动页面,以便在选择选定的操作按钮时显示。但是,我看到了一些针对弹出窗口的响应,而不是针对新的静态移动页面的响应。
var k = 0;
for (var i = 0; i < 300; i++) {
var row = {};
row["firstname"] = firstNames[k];
data[i] = row;
k++;
}
var source =
{
localdata: data,
datatype: "array"
};
var dataAdapter = new $.jqx.dataAdapter(source);
$('#dropdownlist').jqxDropDownList({
selectedIndex: 0, checkboxes: true, theme: theme,
autoDropDownHeight: true, source: dataAdapter,
displayMember: "firstname", valueMember: "notes",
itemHeight: 70, height: 40, width: '90%',
renderer: function (index, label, value) {
var datarecord = data[index];
var imgurl = '../../images/' + label.toLowerCase()
+ '.png';
var img = '<img height="50" src="' + imgurl + '"/>';
var table = '<table><tr><td style="width: 55px;
" rowspan="2">'
+ '</td><td>' + datarecord.firstname + " " + '</td></tr><tr><td>'
+ '</td></tr></table>';
return table;
}
});
initSimulator("dropdownlist");
});
</script>
</head>
<body class='default'>
<div id="demoContainer" class="device-mobile">
<div id="container" class="device-mobile-container">
<h3 style="margin-left: 5%; margin-top:
20px;">Select employees:</h3>
<div style="margin-left: 5%;" id="dropdownlist"></div>
</div>
</div>
<input type="button" id="btnSelected" value="Get Selected" />
第二页的代码将用于从上面列出的代码中捕获结果:
<table id="dataAdapter" name = "firstnames" class="OutlinePage">
<thead class="OutlineText">
<tr>
<td>Name</td>
<td></td>
<td></td>
</tr>
</thead>
<tbody class=OutlineText">
</tbody>
</table>
</div>
</body>
<script>
function AddData() {
{
var rows = "";
var name = document.getElementById("firstnames").value;
var position = document.getElementById("array").value;
rows += "<td>" + name + "</td><td>" + position + "</td>";
var tbody = document.querySelector("#list tbody");
var tr = document.createElement("tr");
tr.innerHTML = rows;
tbody.appendChild(tr)
//
}
}
function ResetForm() {
document.getElementById("firstnames").reset();
}
</script></h1>
<script>
// from checkboxes7.html
document.getElementById("write").innerHTML = window.location.search;
</script>
<script>
function getParameterByName(name, url) {
if (!url) url = window.location.href;
name = name.replace(/[\[\]]/g, '\\$&');
var regex = new RegExp('[?&]' + name + '(=([^&#]*)|&|#|$)'),
results = regex.exec(url);
if (!results) return null;
if (!results[2]) return '';
return decodeURIComponent(results[2].replace(/\+/g, ' '));
}</script>
<script>
function show() {
document.getElementById("write").innerHTML = name;
}
var sn = getParameterByName('firstnames');
document.getElementById("write").innerHTML = sn;
</script>
</p>
</html>
解决方案
有很多东西没有定义,没有合适的库我无法测试。发现一些语法问题,所以我清理了这些和代码。
$(function() {
var k = 0;
for (var i = 0; i < 300; i++) {
var row = {};
row.firstname = firstNames[k];
data[i] = row;
k++;
}
var source = {
localdata: data,
datatype: "array"
};
var dataAdapter = new $.jqx.dataAdapter(source);
$('#dropdownlist').jqxDropDownList({
selectedIndex: 0,
checkboxes: true,
theme: theme,
autoDropDownHeight: true,
source: dataAdapter,
displayMember: "firstname",
valueMember: "notes",
itemHeight: 70,
height: 40,
width: '90%',
renderer: function(index, label, value) {
var datarecord = data[index];
var imgurl = '../../images/' + label.toLowerCase() + '.png';
var img = '<img height="50" src="' + imgurl + '"/>';
var table = '<table><tr><td style="width: 55px;" rowspan="2">';
table += '</td><td>' + datarecord.firstname + " " + '</td></tr><tr><td>';
table += '</td></tr></table>';
return table;
}
});
initSimulator("dropdownlist");
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="demoContainer" class="device-mobile">
<div id="container" class="device-mobile-container">
<h3 style="margin-left: 5%; margin-top: 20px;">Select employees:</h3>
<div style="margin-left: 5%;" id="dropdownlist"></div>
</div>
</div>
<input type="button" id="btnSelected" value="Get Selected" />
希望有帮助。
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