bash - 如何从文本中提取特定字符串

Question

我有一个这样的 .txt 文件，

26S proteasome non-ATPase regulatory subunit 1 OS=Homo sapiens OX=9606 GN=PSMD1 PE=1 SV=1
Tensin-1 OS=Homo sapiens OX=9606 GN=TNS1 PE=1 SV=1
Integrin-linked protein kinase OS=Homo sapiens OX=9606 GN=ILK PE=1 SV=1
Glucose-6-phosphate isomerase (Fragment) OS=Homo sapiens OX=9606 GN=GPI PE=1 SV=1
Fibulin-5 OS=Homo sapiens OX=9606 GN=FBLN5 PE=1 SV=1
Tropomyosin alpha-1 chain (Fragment) OS=Homo sapiens OX=9606 GN=TPM1 PE=1 SV=1
Cadherin-1 OS=Homo sapiens OX=9606 GN=CDH1 PE=1 SV=1

我只想在之后提取字符串GN=

我想要这样的输出

PSMD1
TNS1
ILK
GPI
FBLN5
TPM1
CDH1

标签： bashmacos

Answer 1

这可能对您有用：

$ grep -Po 'GN=\K[^[:space:]]+' file
PSMD1
TNS1
ILK
GPI
FBLN5
TPM1
CDH1