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mysql - mysql对每一行求和

问题描述

查询得到如下结果

表价格（项目 int，金额 int，数量 int，）

+-------+-------+----------+
| item  | price | quantity |
+-------+-------+----------+
| box 1 |  1000 |        4 |
| box 2 |  2000 |        1 |
| box 3 |  3000 |        6 |
+-------+-------+----------+

结果

+-------+-------+----------+-----------+-------+
| item  | price | quantity | sub total | total |
+-------+-------+----------+-----------+-------+
| box 1 |  1000 |        4 |      4000 | 16000 |
| box 2 |  2000 |        1 |      2000 | 18000 |
| box 3 |  3000 |        6 |     18000 | 36000 |
+-------+-------+----------+-----------+-------+

标签： mysqlsumrow

解决方案

如果你的mysql版本低于8.0，你可以试试下面

select 
    item,price,quantity,price*quantity as total, 
    @totalall:= @totalall + price*quantity as TotalAll
from price, (Select @totalall:= 0) as totalall;

或者，如果您的 mysql vsersion 8.0+，那么您可以在下面尝试 -

SELECT 
    item,price,quantity,price*quantity as total, 
    SUM(price*quantity) OVER(ORDER BY item) AS TotalAll
FROM price;

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