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java - 如何在 Java (Eclipse) 中对角检查二维字符数组中的字符串

问题描述

我从用户那里得到一个单词列表作为输入，并将他们的输入存储在 String[] 数组中。然后我创建一个名为 letterGrid 的 char[][] 数组，其中填充了随机字母和用户提供的单词。当 letterGrid 显示在控制台屏幕上时，用户必须输入他们想要查找的单词。然后程序将检查输入的单词是否水平、垂直或对角显示，并将其打印为s location. I have the checkHorizontal and checkDiagonal methods working fine, but I am having a problem at checkVertical. For example, my sample input of words was红色、橙色、黄色、绿色、蓝色、紫色、彩虹色。, and下面是输出网格：

单词搜索错误 - 控制台屏幕

如您所见，当我输入黄色（长度为 6 个字母）时，程序输出了单词的位置，但随后出现了超出范围的错误。

编辑代码

以下是应@Igor Khvostenkov 要求的其余代码：

 
 	private String word; // This variable will be the user`s input when they chose to search for a word they have entered
    private int rowLocation; // This variable will represent the row number in which the word is at
    private int colLocation; // This variable will represent the column number in which the word is at
 
 // Create a method to compare the user`s word to the elements in the letter grid
 public void compare (String word) {
    	
        for (int row = 0; row < letterGrid.length - 1; row++) {
        	
            for (int col = 0; col < letterGrid[row].length - 1; col++) {
            	
                if (letterGrid[row][col] == word.charAt(0)) {

                    rowLocation = row;
                    colLocation = col;

                    wordContains(); // Call on method to see if the word entered by the user appears horizontally, vertically, or diagonally
                    
                }//end of if
                
            }//end of inner for loop
            
        }//end of outer for loop
        
    }//end of compare(word)
    
    // Create a method that will check the direction of the user`s word input

    public void wordContains() {
    	
        checkHorizontal(); // Checking if the word appears horizontally
        checkVertical(); // Checking id the word appears vertically
        checkDiagonal(); // Checking if the word appears diagonally
        
    }//end of wordContains()
    
    // Create a method to check if the user`s word appears HORIZONTALLY in the letter grid

    public void checkHorizontal() {
    	
        for (int i = 1; i < (word.length()); i++) {
        	
            if (colLocation + i > letterGrid[0].length - 1) {
            	
                return;
                
            } else if(letterGrid[rowLocation][colLocation + i] != word.charAt(i)) {
            	
               return;
               
            }//end of if..else if
            
        }//end of for loop
        
        System.out.println(word + " found horizontally at row " + rowLocation + " and column " + colLocation); // Word found!!
        System.out.println();

        return;

    }//end of checkHorizontal()

    // Create a method to check if the user`s word appears VERTICALLY in the letter grid
    
    public void checkVertical() {
    
        for (int i = 1; i < (word.length()); i++) {
        
            if (rowLocation + i > letterGrid.length - 1 && colLocation + i > letterGrid[0].length) {
                
            	return;
            	
            } else if (letterGrid[rowLocation + i][colLocation] != word.charAt(i)) {
            	
            	return;
            	
            }//end of if..else if
            
        }//end of for loop
        
        System.out.println(word + " found vertically at row " + rowLocation + " and column " + colLocation); // Word found!!
        System.out.println();          
        
    }//end of checkVertical()
    
    // Create a method to check if the user`s word appears DIAGONALLY in the letter grid

    public void checkDiagonal() {
    	
        for (int i = 1; i < (word.length()); i++) {
        	
            if (colLocation + i > letterGrid[0].length - 1 || rowLocation + i > letterGrid.length - 1) {
            	
                return;
                
            } else if (letterGrid[rowLocation + i][colLocation + i] != word.charAt(i)) {
            	
                return;
                
            }//end of if..else if
            
        }//end of for loop
        
        System.out.println(word + " found diagonally at row " + rowLocation + " and column " + colLocation); // Word found!!
        System.out.println("");
        
    }//end of checkDiagonal()

我t seem to know why this is happening, and how I can fix this. I am not that familiar with ArrayIndexOutofBounds Exceptions as I barely go through them, but recently I have been and I一直在尝试理解问题并寻找帮助我解决问题的方法。

标签： javamultidimensional-arrayindexoutofboundsexceptionwordsearch

解决方案

代码中的问题在于您的 if 条件，checkVertical()因为行和列可能是第一个或最后一个，但您应该检查行或列。由于Y在第一行和第二列中找到第一个代码然后继续扫描，您的黄色示例失败，然后继续扫描，最后，它Y在最后一行中找到并检查rowLocation + i > letterGrid.length - 1 && colLocation + i > letterGrid[0].length跳过的内容，然后调用elsewhich 将 1 添加到该行，结果为绑定数组。这应该有效：

 public void checkVertical() {

        for (int i = 1; i < (word.length()); i++) {

            if (rowLocation + i > letterGrid.length - 1 || colLocation + i > letterGrid[0].length) {

                return;

            } else if (letterGrid[rowLocation + i][colLocation] != word.charAt(i)) {

                return;

            }//end of if..else if

        }//end of for loop

        System.out.println(word + " found vertically at row " + rowLocation + " and column " + colLocation); // Word found!!
        System.out.println();

    }//end of checkVertical()

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