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python - 如何根据osmnx上的一些“手动选择”节点绘制路径？

问题描述

我想在 osmnx 地图上绘制一条路线。当我尝试手动创建路线时，它不起作用。

import networkx as nx
import osmnx as ox
import requests 
import matplotlib.cm as cm
import matplotlib.colors as colors
location_point = (50.345559621674596, 7.576892382877531)
G = ox.graph_from_point(location_point, distance=500, 
distance_type='network', network_type='walk')
origin_node = ox.get_nearest_node(G, location_point)
destination_node = list(G.nodes())[-1]
fig, ax = ox.plot_graph(G)
G=nx.convert_node_labels_to_integers(G)
route = [3 ,1 ,41 ,40 ,98 ,62 ,67 ,107 ,94 ,83 ,39 ]
ox.plot_route_folium(G,route)

我期待一张带有彩色路线的地图，但我得到了这个错误。

    ---------------------------------------------------------------------------
    IndexError                                Traceback (most recent call last)
    <ipython-input-9-11235dc07ef4> in <module>()
    ----> 1 ox.plot_route_folium(G,route)

    ~\Anaconda3\lib\site-packages\osmnx\plot.py in plot_route_folium(G, route, route_map, popup_attribute, tiles, zoom, fit_bounds, route_color, route_width, route_opacity)
        907     gdf_edges = graph_to_gdfs(G, nodes=False, fill_edge_geometry=True)
        908     route_nodes = list(zip(route[:-1], route[1:]))
    --> 909     index = [gdf_edges[(gdf_edges['u']==u) & (gdf_edges['v']==v)].index[0] for u, v in route_nodes]
        910     gdf_route_edges = gdf_edges.loc[index]
        911 

    ~\Anaconda3\lib\site-packages\osmnx\plot.py in <listcomp>(.0)
        907     gdf_edges = graph_to_gdfs(G, nodes=False, fill_edge_geometry=True)
        908     route_nodes = list(zip(route[:-1], route[1:]))
    --> 909     index = [gdf_edges[(gdf_edges['u']==u) & (gdf_edges['v']==v)].index[0] for u, v in route_nodes]
        910     gdf_route_edges = gdf_edges.loc[index]
        911 

    ~\Anaconda3\lib\site-packages\pandas\core\indexes\base.py in __getitem__(self, key)
       2082 
       2083         if is_scalar(key):
    -> 2084             return getitem(key)
       2085 
       2086         if isinstance(key, slice):

    IndexError: index 0 is out of bounds for axis 0 with size 0

如果我尝试通过最短路径算法找到一条路线并将其可视化在地图上，它工作正常。但我想绘制这条特定路线

标签： pythonroutesosmnx

解决方案

OSMnx 使用节点的 OSMID。当您运行时G=nx.convert_node_labels_to_integers(G)，您会覆盖这些 OSMID。但是，您并没有在图形边缘u和v属性中覆盖它们，它们标识了边缘的端点（使用 OSMID）。

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