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java - 如何添加是或否的重置游戏？游戏Java

问题描述

我不知道如何使用是或否输入用户添加重置游戏我已经尝试了很多解决方案但它不起作用。

这是我的代码：

import java.util.Scanner;

public class Pr16 {

public static void main(String[] args) {

    Scanner in = new Scanner(System.in);
    String a = "Stone";
    String b = "Scissors";
    String c = "Paper";
    //a > b
    //b > c
    //c > a

    System.out.println("Player one choose:");

    String x = in.nextLine();

    System.out.println("Player two choose:");

    String y = in.nextLine();

    String answer = "";

    do {
            if ((x.equalsIgnoreCase(a) && (y.equalsIgnoreCase(b)))) {
                System.out.println("Player one won");
            } else if ((x.equalsIgnoreCase(b) && (y.equalsIgnoreCase(c)))) {
                System.out.println("Player one won");
            } else if ((x.equalsIgnoreCase(c) && (y.equalsIgnoreCase(a)))) {
                System.out.println("Player one won");
            } else {
                System.out.println("Player two won");
            }
        System.out.println("Do you want to play again? YES / NO");
        answer= in.nextLine();
        }

        while (answer.equalsIgnoreCase("YES"));
        if (answer.equalsIgnoreCase("NO")){
            System.out.println("Goodbye!");
        }
    }
}

有什么方法可以将游戏重置添加到我上面的代码中？任何意见，将不胜感激。

标签： java

解决方案

试试下面的代码：

public static void main(String[] args) {

        Scanner in = new Scanner(System.in);
        String a = "Stone";
        String b = "Scissors";
        String c = "Paper";
        //a > b
        //b > c
        //c > a
            String answer = "";
        do {
            System.out.println("Player one choose:");

            String x = in.nextLine();

            System.out.println("Player two choose:");

            String y = in.nextLine();

            answer = "";

            if ((x.equalsIgnoreCase(a) && (y.equalsIgnoreCase(b)))) {
                System.out.println("Player one won");
            } else if ((x.equalsIgnoreCase(b) && (y.equalsIgnoreCase(c)))) {
                System.out.println("Player one won");
            } else if ((x.equalsIgnoreCase(c) && (y.equalsIgnoreCase(a)))) {
                System.out.println("Player one won");
            } else {
                System.out.println("Player two won");
            }
            System.out.println("Do you want to play again? YES / NO");
            answer= in.nextLine();
        }

        while (answer.equalsIgnoreCase("YES"));
        if (answer.equalsIgnoreCase("NO")){
            System.out.println("Goodbye!");
        }
    }

如果你愿意，你可以制作 2 个类，这样会更干净，但这个答案将在你的主要功能中完成工作，不需要其他类

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