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python - 如何在 Python 的另一个循环中正确编写一个 for 循环？

问题描述

我试图在尽可能多的迭代中循环现有的 for 循环，这样我就不必手动执行此操作。我的嵌套循环根据他们的偏好将医生与医院进行匹配。这里 get 函数中的 1.0 指的是 rank 1。

这是我到目前为止想出的（代码中的 # 解释得更多）：

def hospital_ranking_of_doctor(hospital, doctor):
    return ranking_by_hospitals2[hospital][doctor]

#free_doctors is currently a range (0,10)
for i in range(len(free_doctors)):
    #Make a dictionary with name Round_(i+1) (To start at Round_1)
    Round_(str(i+1)) = {}
    #Start off with same values as last round, this action should not be performed in the first round
    Round_(str(i+1)).update(Round_(str(i))
    Round_(str(i+1))_values = list(Round_(str(i+1)).values())
    for Doctor_ in ranking_by_doctors:
        favored_hospital = ranking_by_doctors[Doctor_].get(1.0 + i) #Hospitals are ranked from 1.0 - 10.0, need 1.0 or would start at 0 and get error
        favored_hospital_doctor = Doctor_
#If the hospital and doctor have not been assigned to a match before, assign the current hospital to the current doctor
        if favored_hospital not in Round_(str(i+1)) and favored_hospital_doctor not in Round_(str(i+1))_values:
                Round_(str(i+1))[favored_hospital] = Doctor_
#If the doctor has been assigned to a match before, continue with the next doctor
    elif favored_hospital_doctor in Round_(str(i+1))_values:
        continue
#If the hospital has been assigned to a match before, check if the previously assigned doctor is ranked higher (e.g 2.0 instead of 1.0)
#When this is indeed the case, the hospital prefers the new doctor over the old doctor, so assign the new doctor as its match    
    else:
        previously_assigned_doctor = Round_(str(i+1))[favored_hospital]
        if hospital_ranking_of_doctor(favored_hospital, previously_assigned_doctor) > hospital_ranking_of_doctor(favored_hospital, Doctor_):
            Round_(str(i+1)[favored_hospital] = Doctor_
Matches['Round_'str(i+1)] = Round_(str(i+1))
Matches

自由医生：

['Doctor_10', 'Doctor_6', 'Doctor_5', 'Doctor_9', 'Doctor_1', 'Doctor_4', 'Doctor_3', 'Doctor_7', 'Doctor_2', 'Doctor_8']

嵌套的 for 循环有效，但循环循环会给我语法错误。在它说的任何地方（str(i+1)我会在新的命令代码中手动写入之前的数字（因此，第 1 轮使用 1 get(1.0)，第 2 轮使用 2。get(2.0)这对于 10 位医生和 10 家医院的数据集是可行的。但是，我想增加此数据集的大小然后手动执行此操作变得不可持续。所以我想编写一个循环自动为我执行此操作，然后字典匹配应显示所有十轮以及在这些轮中获得的匹配。

range(len(free_doctors))如果循环一直持续到所有医生和医院都匹配，甚至比使用, 更好。

标签： pythonloopsdictionaryfor-loopmatching

解决方案

看起来你正在尝试解决“稳定的婚姻”问题。不是夫妻无法“交易”，而是医生和医院，但结构是一样的：学生和学校等。

https://gist.github.com/joyrexus/9967709是谷歌的第一个热门"Stable Marriage" Python，它可能会做你想做的事。

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