python - Keras：乘以常数

Question

可以从Kerasx*a的输入中获得吗？size(None, None, 3)例如，输入x和constant a: x(batch,None,None,1024)*a(batch,1)。

我size (64, 64, 3)在火车中使用输入，但测试数据应使用可变输入大小。无法调整测试大小以进行公平的图像处理。

我尝试 Lambda function(lambda x : x * a)(seq)。然后，我的代码没有问题。然后，我启动 model.fit 函数，我得到了错误：

------------->>tensorflow.python.framework.errors_impl.InvalidArgumentError: Incompatible shapes: [7,4,4,1024] vs. [7,1]. 

.

conv5 = Conv2D(1024, 3, activation = 'relu', padding = 'same', kernel_initializer = 'he_normal')(pool4)
conv5 = Conv2D(1024, 3, activation = 'relu', padding = 'same', kernel_initializer = 'he_normal')(conv5)

conv_c = Conv2D(num_classes, 1, activation='softmax')(conv5)
conv_c1 = GlobalAveragePooling2D(name="class_output")(conv_c)

conv_c1_1 = conv_c1[:, 0:1]
conv_c1_2 = conv_c1[:, 1:2]
conv_c1_3 = conv_c1[:, 2:3]

conv5_b = Lambda(lambda x: x * conv_c1_1)(conv5) #conv5:Tensor(shape=(?, 4, 4, 1024))
conv5_h = Lambda(lambda x: x * conv_c1_2)(conv5) #conv_c1_1: Tensor(shape=(?, 1))
conv5_r = Lambda(lambda x: x * conv_c1_3)(conv5)

标签： pythontensorflowkeras