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mysql - 连接来自旋转 mysql 的结果值

问题描述

我试图在旋转后获得一个连接的字符串值。

目前，只有一个值并且工作正常。

这是查询：

DROP PROCEDURE IF EXISTS getAllUserLunchReport;
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `getAllUserLunchReport`(IN `start_date` DATETIME, IN `end_date` DATETIME)
BEGIN

SET GLOBAL group_concat_max_len=4294967295;
SET @SQL = NULL;
SET @start_date = DATE(start_date);
SET @end_date = DATE(end_date);

    SELECT
    COALESCE(GROUP_CONCAT(DISTINCT
    CONCAT(
    'SUM(CASE WHEN date = "',DATE(issuedDateTime),'" AND lunchStatus = 1 THEN (SELECT CONCAT((SELECT rate FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), "," ,(SELECT rate FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1))) ELSE 0 END) AS `',DATE(issuedDateTime),'`'
    ) ORDER BY issuedDateTime
), '0 as `NoMatchingRows`') INTO @SQL

        FROM `lunch_status` 
        WHERE DATE(issuedDateTime) BETWEEN @start_date AND @end_date;

    SET @SQL 
    = CONCAT
    (
    '
        SELECT concat(u.firstname," ",u.lastname) as Employee, w.*
        FROM users u
        INNER JOIN
        (SELECT userId, ', @SQL, ' 
        FROM
        (
            SELECT userId, lunchStatus, DATE(issuedDateTime) as date 
            FROM `lunch_status` 
            WHERE DATE(issuedDateTime) BETWEEN "',@start_date,'" AND "',@end_date,'" 
        ) as a
        GROUP BY userId) w
        ON u.id = w.userId
        ORDER BY Employee;
    '
    );

PREPARE stmt FROM @SQL;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;


END$$
DELIMITER ;

我只得到第一个值，没有我试图连接的其他值。

以下是我对结果的预期：

employee    |   2019-1-15  |  2019-1-16
----------------------------------------
Jack        |   30,140     |  30,140

但是，单独执行连接查询是可行的。

注意：在上面的存储过程中，如果删除分隔符，则会连接值。CONCAT((select ...), (select...))给30140.

可能是 的问题quotes，但我已经尝试了各种方法。

仅供参考，这是@SQL第一次查询后产生的结果：

SUM(CASE WHEN date = "2019-01-15" AND lunchStatus = 1 THEN (SELECT CONCAT((SELECT rate FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), ",", (SELECT rate FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1))) ELSE 0 END) AS `2019-01-15`,
SUM(CASE WHEN date = "2019-01-16" AND lunchStatus = 1 THEN (SELECT CONCAT((SELECT rate FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), ",", (SELECT rate FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1))) ELSE 0 END) AS `2019-01-16`

看起来有效。

编辑：它似乎与“整数”值一起工作正常。例如

CONCAT((SELECT rate FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), "111" ,(SELECT rate FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1))

给301140.

但是对于其他字符,/./-/_，只显示第一个参数：30。

标签： mysqlsqlconcatgroup-concat

解决方案

,当您在中包含时您的代码不起作用的原因CONCAT是因为它CONCAT在 a 内SUM，并且它无法解释30,140为数字，它可以这样做30140（因此没有分隔符你会得到一个结果）。在不了解表数据和所需结果的更多详细信息的情况下，很难准确说明如何解决问题，但也许您想要这样的东西：

CASE WHEN date = "2019-01-15" AND lunchStatus = 1 THEN CONCAT((SELECT SUM(rate) FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), ",", (SELECT SUM(rate) FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1)) ELSE 0 END) AS `2019-01-15`

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