php - Laravel 5.7:构建时目标不可实例化
问题描述
我知道有很多答案,但我无法真正解决这个问题。
我确实按照这个答案(如何在 Laravel 中制作 REST API 第一个 Web 应用程序)在 Laravel 5.7 上创建存储库/网关模式
我在 github 上也有“项目”,如果有人真的想要测试/克隆/参见:https ://github.com/sineverba/domotic-panel/tree/development (开发分支)
应用程序\接口\局域网接口
<?php
/**
* Interface for LAN models operation.
*/
namespace App\Interfaces;
interface LanInterface
{
public function getAll();
}
应用\提供者\服务提供者
<?php
namespace App\Providers;
use Illuminate\Support\ServiceProvider;
use Illuminate\Support\Facades\Schema;
class AppServiceProvider extends ServiceProvider
{
/**
* Bootstrap any application services.
*
* @return void
*/
public function boot()
{
/**
* Solve the "Key too long" issue
*
* @see https://laravel-news.com/laravel-5-4-key-too-long-error
*/
Schema::defaultStringLength(191);
}
/**
* Register any application services.
*
* @return void
*/
public function register()
{
$this->app->register(RepositoryServiceProvider::class);
}
}
App\Providers\RepositoryServiceProvider
<?php
namespace App\Providers;
use Illuminate\Support\ServiceProvider;
class RepositoryServiceProvider extends ServiceProvider
{
public function register()
{
$this->app->bind(
'app\Interfaces\LanInterface', // Interface
'app\Repositories\LanRepository' // Eloquent
);
}
}
应用\网关\局域网网关
<?php
/**
* The gateway talks with Repository
*/
namespace App\Gateways;
use App\Interfaces\LanInterface;
class LanGateway
{
protected $lan_interface;
public function __construct(LanInterface $lan_interface) {
$this->lan_interface = $lan_interface;
}
public function getAll()
{
return $this->lan_interface->getAll();
}
}
应用程序\存储库\LanRepository
<?php
/**
* Repository for LAN object.
* PRG paradigma, instead of "User"-like class Model
*/
namespace App\Repositories;
use App\Interfaces\LanInterface;
use Illuminate\Database\Eloquent\Model;
class LanRepository extends Model implements LanInterface
{
protected $table = "lans";
public function getAll()
{
return 'bla';
}
}
我确实App\Providers\RepositoryServiceProvider::class,
在providers
部分添加了config\app.php
这终于是控制器了(我知道它不完整):
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Gateways\LanGateway;
class LanController extends Controller
{
private $lan_gateway;
/**
* Use the middleware
*
* @return void
*/
public function __construct(LanGateway $lan_gateway)
{
$this->middleware('auth');
$this->lan_gateway = $lan_gateway;
}
/**
* Display a listing of the resource.
*
* @return \Illuminate\Contracts\Support\Renderable
*/
public function index()
{
$this->lan_gateway->getAll();
return view('v110.pages.lan');
}
}
我得到的错误是
Target [App\Interfaces\LanInterface] is not instantiable while building [App\Http\Controllers\LanController, App\Gateways\LanGateway].
我确实尝试过:
php artisan config:clear
php artisan clear-compiled
解决方案
我认为@nakov 可能是正确的,它区分大小写。我不相信 PHP 本身关心大写/小写命名空间,但是 composer 自动加载器和 Laravel 容器使用 key->value 数组键,它们确实有区分大小写的键,来绑定和检索容器中的类。
为确保名称始终匹配,请尝试使用特殊::class
常量,如下所示:
<?php
namespace App\Providers;
use Illuminate\Support\ServiceProvider;
use App\Repositories\LanRepository;
use App\Interfaces\LanInterface;
class RepositoryServiceProvider extends ServiceProvider
{
public function register()
{
$this->app->bind(
LanInterface::class,
LanRepository::class
);
}
}
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