首页 > 解决方案 > 如何遍历列表网络抓取的表格列并为每个项目返回一个结果?

问题描述

我有一个 python 代码,可以通过网络抓取正确的数据,但 guest 列中有多个字符串,目前只提取一个。那么,我如何遍历该列单元格中的列表并将 3 个客人作为单独的列返回,希望每个客人 1、客人2、客人3?谢谢

import requests
import pandas as pd
from bs4 import BeautifulSoup
import numpy as np

df = pd.DataFrame(columns=(['NoInSeason', 'Guests', 'Winner', 'OriginalAirDate']))
page = requests.get("https://en.wikipedia.org/wiki/List_of_QI_episodes")
soup = BeautifulSoup(page.content, "lxml")
my_tables = soup.find_all("table",{"class":"wikitable plainrowheaders wikiepisodetable"})
for table in my_tables:
    table_rows = table.find_all("tr")
    for tr in table_rows:
        td = tr.find_all("td")
        if len(td) == 5:
            NoInSeason = td[0].find(text=True)
            Guests = td[2].find_all(text=True)
            Winner  = td[3].find(text=True)
            OriginalAirDate = td[4].find(text=True) 
            if len(Guests) == 3:
                Guest1 = Guests[0]
                Guest2 = Guests[1]
                Guest3 = Guests[2]
                df = df.append({'NoInSeason': NoInSeason, 'Guest1' : Guest1, 'Guest2' : Guest2, 'Guest3' : Guest3, 'Winner': Winner, 'OriginalAirDate' : OriginalAirDate}, ignore_index=True)
df.to_csv("output.csv")
print(df)

标签: pythonweb-scraping

解决方案


这是你要找的吗?

df = pd.DataFrame(columns=(['NoInSeason', 'Guest 1', 
'Guest 2', 'Guest 3', 'Winner', 'OriginalAirDate']))
page = 
  requests.get("https://en.wikipedia.org/wiki/List_of_QI_episodes")
soup = BeautifulSoup(page.content, "lxml")
my_tables = soup.find_all("table",{"class":"wikitable plainrowheaders wikiepisodetable"})
for table in my_tables:
    table_rows = table.find_all("tr")
    for tr in table_rows:
        td = tr.find_all("td")
        if len(td) == 5:
            NoInSeason = td[0].find(text=True)
            Guests = td[2].find_all(text=True)
            Winner  = td[3].find(text=True)
            OriginalAirDate = td[4].find(text=True)
            print(Guests)
            try:
                df = df.append({'NoInSeason': NoInSeason, 'Guest 1' : Guests[0], 'Guest 2' : Guests[1], 'Guest 3' : Guests[2], 'Winner': Winner, 'OriginalAirDate' : OriginalAirDate}, ignore_index=True)
            except IndexError as index_error:
                continue
print(df)

编辑:我看到您更改了代码,现在可以使用吗?在 DataFrame 中包含 Guest1、Guest2 和 Guest3 列会不会更好,这样您就不会得到一个充满 NaN 的“Guests”列?


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