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reactjs - 如何在反应js中的onclick事件上隐藏和显示路由器组件

问题描述

我正在尝试在 REACTJS 中的 onclick 事件上隐藏和显示路由器组件。但没有找到我能做到的方法。帮帮我。这是我的代码-

import React from 'react';
import { BrowserRouter as Router,Route, Link, Switch} from 'react-router-dom';
import SignIn from './SignIn'

export default class Clicksigningin extends React.Component{

    render(){
        return(
            <div>
            <Router>
             <div>
             <Link to={'/SignIn'}><button className='btn btn-danger'>Sign In</button></Link>
             <Switch>
                 <Route exact path = '/SignIn' component = {SignIn} />
             </Switch>
             </div>
            </Router>
        </div>
    )
}

}

标签： reactjsroutingtoggle

解决方案

你可以这样做

import React from "react";
import ReactDOM from "react-dom";

import {
  BrowserRouter as Router,
  Route,
  Link,
  Switch,
  Redirect
} from "react-router-dom";

function SignIn() {
  return "hello";
}

class App extends React.Component {
  state = {
    current: ""
  };

  toggle = () => {
   
    this.setState({ current: this.state.current==''?"SignIn":"" })
      
  };

  render() {
    return (
      <Router>
        <div>
          {this.state.current == "SignIn" ? (
            <Redirect to="/SignIn" />
          ) : (
            <Redirect to="" />
          )}
          <button className="btn btn-danger" onClick={this.toggle}>
            Sign In
          </button>
          <Switch>
            <Route exact path="/SignIn" component={SignIn} />
          </Switch>
        </div>
      </Router>
    );
  }
}

const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);

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