首页 > 解决方案 > 在 keras 中获取中间层的输出会引发名称错误

问题描述

我想可视化胶囊网络中的层。为此,我需要中间层的形状。代码如下:

from keras.models import Model
model = Sequential()
conv1 = model.add(Conv2D(256, (9, 9), padding='valid', strides = 1, input_shape = (28, 28, 1), activation = 'relu', name = 'conv1'))
model.add(Conv2D(256, (9,9), padding='valid', strides = 2, name = 'primarycaps_conv2d'))
model.add(keras.layers.core.Reshape([-1,8]))
model.add(keras.layers.core.Lambda(squash, name = 'hello'))

layer_name = 'conv1'
intermediate_layer_model = Model(inputs=model.input,
                             outputs=model.get_layer(layer_name).output)
intermediate_output = intermediate_layer_model.predict(data)

引发以下错误:

NameError: name 'data' is not defined

如何克服这一点?

标签: tensorflowkerasmodellayer

解决方案


参考this,我得到了如下解决方案:

model = Sequential()
conv1 = model.add(Conv2D(256, (9, 9), padding='valid', strides = 1, input_shape = (28, 28, 1), activation = 'relu', name = 'conv1'))
model.add(Conv2D(256, (9,9), padding='valid', strides = 2, name = 'primarycaps_conv2d'))
model.add(keras.layers.core.Reshape([-1,8]))
model.add(keras.layers.core.Lambda(squash, name = 'hello'))

idx = 3  # index of desired layer
input_shape = model.layers[idx].get_output_shape_at(0)
print(input_shape)

得到输出形状如下:

(None, 1152, 8).

解决了获取特定层输出的问题。


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