首页 > 解决方案 > 生命游戏程序 C Sharp

问题描述

所以我正在尝试编写康威的生命游戏,但我不知道如何处理它检查它们的部分?有任何想法吗?我已将区域标记为“此处的模拟代码”

我不需要你为我做这件事,我只需要一个关于如何处理这部分过程的提示,因为我不知道如何检查阵列周围的区域,看看有多少活点存在,等等.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Gameoflife
{
class Program
{
    static int[,] currentgeneration = new int[Console.LargestWindowHeight + 1, Console.LargestWindowWidth + 1];
    static int[,] nextgeneration = new int[Console.LargestWindowHeight + 1, Console.LargestWindowWidth + 1];

    static void Main(string[] args)
    {
        ConsoleColor cellcolour = ConsoleColor.Green;
        ConsoleColor backgroundcolour = ConsoleColor.Black;

        Introduction();

        Console.Title = "GAME OF LIFE SIMULATION";
        int worldwidth = Console.LargestWindowWidth;
        int worldheight = Console.LargestWindowHeight;
        Console.SetWindowSize(worldwidth, worldheight);
        Console.SetWindowPosition(0, 0);




        setupworld(worldwidth, worldheight, cellcolour, backgroundcolour);




        int generation = 0;
        DrawWorld(worldwidth, worldheight, cellcolour, backgroundcolour, generation);

        // SIMULATION CODE HERE!



        generation++;
        for (int row = 1; row < worldheight; row++)
        {

            for (int col = 1; col < worldwidth; col++)

            {

                currentgeneration[row, col] = nextgeneration[row, col];

            }

        }
        DrawWorld(worldwidth, worldheight, cellcolour, backgroundcolour, generation);

    }






    //---------------------------------------------------------------------------------------------------

    static void Introduction()
    {
        Console.WriteLine("CONWAY'S GAME OF LIFE");
        Console.WriteLine();
        Console.WriteLine("To set up your starting world use the following keys..");
        Console.WriteLine("Arrow keys  - move around the screen");
        Console.WriteLine("Space Bar   - places a cell in that location");
        Console.WriteLine("Escape key  - To end setup");
        Console.WriteLine();
        Console.WriteLine("Hit any key to continue");
        Console.ReadKey();
        Console.Clear();
    }




    //-------------------------------------------------------------------------------------------------

    static void setupworld(int worldwidth, int worldheight, ConsoleColor cellcolour, ConsoleColor backgroundcolour)
    {
        Boolean setupcomplete = false;
        int cursorx = 1; 
        int cursory = 1; 
        Console.SetCursorPosition(cursorx, cursory);
        while (!setupcomplete)
        {
            if (Console.KeyAvailable)
            {
                ConsoleKeyInfo cki = Console.ReadKey();
                switch (cki.Key)
                {
                    case ConsoleKey.UpArrow:
                        if (cursory > 1)
                        {
                            cursory = cursory - 1;
                        }
                        break;

                    case ConsoleKey.DownArrow:
                        if (cursory < Console.LargestWindowHeight - 1)
                        {
                            cursory = cursory + 1;
                        }
                        break;

                    case ConsoleKey.LeftArrow:
                        if (cursorx > 1)
                        {
                            cursorx = cursorx - 1;
                        }
                        break;

                    case ConsoleKey.RightArrow:
                        if (cursorx < Console.LargestWindowWidth - 1)
                        {
                            cursorx = cursorx + 1;
                        }
                        break;

                    case ConsoleKey.Spacebar:
                        currentgeneration[cursory, cursorx] = 1;
                        break;

                    case ConsoleKey.Escape:
                        setupcomplete = true;
                        break;
                }
                DrawWorld(worldwidth, worldheight, cellcolour, backgroundcolour, 0);
                Console.SetCursorPosition(cursorx, cursory);
            }

        }
        Console.SetCursorPosition(15, 0);
        Console.BackgroundColor = ConsoleColor.White;
        Console.ForegroundColor = ConsoleColor.Black;
        Console.Write("Press Any key to now start the simulation");
        Console.ReadKey();
    }


    //-----------------------------------------------------------------------------------------------------

    static void DrawWorld(int worldwidth, int worldheight, ConsoleColor cellcolour, ConsoleColor backgroundcolour, int generation)
    {
        Console.BackgroundColor = ConsoleColor.Black;
        Console.Clear();
        Console.Write("Generation: {0}", generation);
        for (int r = 0; r < worldheight; r++)
        {
            for (int c = 0; c < worldwidth; c++)
            {
                if (currentgeneration[r, c] == 1)
                {
                    Console.SetCursorPosition(c, r);
                    Console.BackgroundColor = cellcolour;
                    Console.Write(" ");
                    Console.BackgroundColor = backgroundcolour;
                }
            }  
        } 
    }
}
} 

标签: c#conways-game-of-life

解决方案


首先用简单的英语写下规则:

  • 任何少于两个活邻居的活细胞都会死亡,就像人口不足一样。
  • 任何有两三个活邻居的活细胞都可以活到下一代。
  • 任何有超过三个活邻居的活细胞都会死亡,就像人口过剩一样。
  • 任何只有三个活邻居的死细胞都会变成活细胞,就像通过繁殖一样。

您现在的工作是将这些简单的英语语句转换为代码。要使代码正常工作,您必须知道它需要哪些输入。所以我们需要检查这些语句以查看它的计算结果:

  • 任何少于两个活邻居的细胞都会死亡,就像人口不足一样。
  • 任何有两三个活邻居的细胞都可以活到下一代。
  • 任何有超过三个活邻居的细胞都会死亡,就像人口过剩一样。
  • 任何只有三个活邻居的细胞都会变成活细胞,就像通过繁殖一样。

基于此分析,我们现在知道我们的代码将需要两个输入:

  1. 它需要知道当前单元格是否还活着
  2. 它需要知道有多少相邻的细胞是活着的。

要计算细胞是否还活着,我假设你会查看currentgeneration[r,c].

要计算有多少相邻的细胞是活着的,您需要查看以下所有内容:

currentgeneration[r-1,c-1] 
currentgeneration[r-1,c  ] 
currentgeneration[r-1,c+1] 
currentgeneration[r  ,c-1] 
currentgeneration[r  ,c  ] 
currentgeneration[r  ,c+1] 
currentgeneration[r+1,c-1] 
currentgeneration[r+1,c  ] 
currentgeneration[r+1,c+1] 

因此,您的代码需要检查所有这些元素并计算活动的元素。

然后,您可以编写一个函数,该函数接受两个输入并确定一个单元格是否还活着:

bool IsAlive(bool wasAlive, int count)
{
    if (wasAlive && count<2) return false;                 // Any live cell with fewer than two live neighbors dies, as if by underpopulation.
    if (wasAlive && (count==2 || count == 3)) return true; // Any live cell with two or three live neighbors lives on to the next generation.
    if (wasAlive && count>=3) return false;                // Any live cell with more than three live neighbors dies, as if by overpopulation.
    if (!wasAlive && count == 3) return true;              // Any dead cell with exactly three live neighbors becomes a live cell, as if by reproduction.
}

现在我们可以编写一个方法来检索要传递给函数的数据:

bool IsAlive(int r, int c)
{
    var count = currentgeneration[r-1,c-1] 
              + currentgeneration[r-1,c  ] 
              + currentgeneration[r-1,c+1] 
              + currentgeneration[r  ,c-1] 
              + currentgeneration[r  ,c  ] 
              + currentgeneration[r  ,c+1] 
              + currentgeneration[r+1,c-1] 
              + currentgeneration[r+1,c  ] 
              + currentgeneration[r+1,c+1];
    var isAlive = ( currentgeneration[r,c] == 1);
    return IsAlive(isAlive, count);
}

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