首页 > 解决方案 > 从python变量中获取年月日

问题描述

我想按年、月和日打破一个变量。这是我得到的:

import datetime
from datetime import date, timedelta
yesterday = date.today() - timedelta(1)
print (yesterday)
year = datetime.date.yesterday.year
month = datetime.date.yesterday.month
day=datetime.date.yesterday.day
print (year)
print (month)
print (day)

我收到 datetime.date 没有属性的错误。我是python的菜鸟,我被困住了,感谢任何帮助

标签: pythonpython-3.xdatevariables

解决方案


你很亲近

import datetime
from datetime import date, timedelta
yesterday = date.today() - timedelta(1)
print (yesterday)
year = yesterday.year
month = yesterday.month
day=yesterday.day
print (year)
print (month)
print (day)

结果是

2019-03-10

2019

3

10


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