首页 > 解决方案 > Pyspark - 拆分一列并取 n 个元素

问题描述

我想取一列并使用字符拆分字符串。像往常一样,我知道方法 split 会返回一个列表,但是在编码时我发现返回的对象只有方法 getItem 或 getField 以及来自 API 的以下描述:

@since(1.3)   
def getItem(self, key):
    """
    An expression that gets an item at position ``ordinal`` out of a list,
    or gets an item by key out of a dict.


@since(1.3)
def getField(self, name):
    """
    An expression that gets a field by name in a StructField.

显然这不符合我的要求,例如对于“A_B_C_D”列中的文本,我想在两个不同列中的“A_B_C_”和“D”之间拆分。

这是我正在使用的代码

from pyspark.sql.functions import regexp_extract, col, split
df_test=spark.sql("SELECT * FROM db_test.table_test")
#Applying the transformations to the data

split_col=split(df_test['Full_text'],'_')
df_split=df_test.withColumn('Last_Item',split_col.getItem(3))

找一个例子:

from pyspark.sql import Row
from pyspark.sql.functions import regexp_extract, col, split
l = [("Item1_Item2_ItemN"),("FirstItem_SecondItem_LastItem"),("ThisShouldBeInTheFirstColumn_ThisShouldBeInTheLastColumn")]
rdd = sc.parallelize(l)
datax = rdd.map(lambda x: Row(fullString=x))
df = sqlContext.createDataFrame(datax)
split_col=split(df['fullString'],'_')
df=df.withColumn('LastItemOfSplit',split_col.getItem(2))

结果:

fullString                                                LastItemOfSplit
Item1_Item2_ItemN                                            ItemN
FirstItem_SecondItem_LastItem                                LastItem
ThisShouldBeInTheFirstColumn_ThisShouldBeInTheLastColumn     null

我的预期结果总是最后一项

fullString                                                LastItemOfSplit
Item1_Item2_ItemN                                            ItemN
FirstItem_SecondItem_LastItem                                LastItem
ThisShouldBeInTheFirstColumn_ThisShouldBeInTheLastColumn  ThisShouldBeInTheLastColumn

标签: apache-sparkpysparkapache-spark-sqlpyspark-sql

解决方案


您可以使用getItem(size - 1)从数组中获取最后一项:

示例

df = spark.createDataFrame([[['A', 'B', 'C', 'D']], [['E', 'F']]], ['split'])
df.show()
+------------+
|       split|
+------------+
|[A, B, C, D]|
|      [E, F]|
+------------+

import pyspark.sql.functions as F
df.withColumn('lastItem', df.split.getItem(F.size(df.split) - 1)).show()
+------------+--------+
|       split|lastItem|
+------------+--------+
|[A, B, C, D]|       D|
|      [E, F]|       F|
+------------+--------+

对于您的情况:

from pyspark.sql.functions import regexp_extract, col, split, size
df_test=spark.sql("SELECT * FROM db_test.table_test")
#Applying the transformations to the data

split_col=split(df_test['Full_text'],'_')
df_split=df_test.withColumn('Last_Item',split_col.getItem(size(split_col) - 1))

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