时间戳

首页 > 解决方案 > 我无法在 GeoDjango (PostGis) 中按城市距离排序

python - 我无法在 GeoDjango (PostGis) 中按城市距离排序

问题描述

距离方法在 GeoDjango (QuerySet) 中不起作用

我的模型：

class City(models.Model):

    name_english = models.CharField(max_length=500, null=True, blank=True)
    site = models.ForeignKey(Site, on_delete=models.CASCADE, null=True, blank=True, verbose_name="city", db_index=True, related_name="city_relate")
    name_city_avito = models.CharField(max_length=500, null=True, blank=True)
    country = models.ForeignKey(Country, on_delete=models.CASCADE, null=True, blank=True, verbose_name="Country", db_index=True, related_name="Country_relate")
    region = models.ForeignKey(Region, on_delete=models.CASCADE, null=True, blank=True, verbose_name="Region", db_index=True, related_name="Region_relate")
    point = models.PointField(blank=True, null=True)

视图.py

class Landing_head(View):

    def get(self, request):
        b = Site.objects.get_current()
        current_location = City.objects.get(site__id=b.id).point

        cities = City.objects.filter(point__distance_lte=(current_location, D(km=200))).distance(current_location).order_by('point_distance')[:1][0]

        for z in cities:
           print(z)

输出错误 'QuerySet' 对象没有属性 'distance'

虽然它在这个版本中工作，但没有按距离排序

class Landing_head(View):

    def get(self, request):
        b = Site.objects.get_current()
        current_location = City.objects.get(site__id=b.id).point

        cities = City.objects.filter(point__distance_lte=(current_location, D(km=200)))
        for z in cities:
            print(z)

标签： pythondjangopostgisgeodjango

解决方案

在 Django 版本 >= 1.9.distance中不存在。

您需要将距离测量注释到查询集，然后按注释字段排序：

cities = City.objects.filter(
    point__distance_lte=(current_location, D(km=200))
).annotate(
    distance=Distance('point', current_location)
).order_by('distance')

推荐阅读