python - 根据 for 循环中的概率打印列表的元素

Question

基于 p 的概率，如果 p < 0.5 我想取 list1 对应位置的字母。

例如：

for i in range(5):
    list1 = ['A', 'B', 'C', 'D', 'E']
    p = np.random.uniform(low= 0.0, high= 1.0, size=5)
    print(p)

输出是：

[ 0.46565909  0.741431    0.65590764  0.87347741  0.38465195]
[ 0.62172525  0.80688763  0.40391766  0.28042554  0.34544989]
[ 0.00138961  0.56959351  0.69043625  0.59473154  0.84042555]
[ 0.18535428  0.63470281  0.27882709  0.78731892  0.63624727]
[ 0.89383216  0.72008758  0.66048462  0.94064897  0.1484418 ] 

因此，根据概率，我希望我的输出是：

['A', 'E']
['C', 'D', 'E']
['A']
['A', 'C']
['E']

标签： pythonlistfor-loopsimulationprobability

Answer 1

用于np.where获取值小于 0.5 的索引，然后打印这些元素：

for i in range(5):
    list1 = ['A', 'B', 'C', 'D', 'E']
    mask = np.where(np.random.uniform(low= 0.0, high= 1.0, size=5) < 0.5)
    print([list1[i] for i in mask[0]])

#output (The output is stochastic meaning they will change on each iteration unless you use fixed random state)
['C']
['A', 'B', 'C', 'E']
['D', 'E']
['A', 'C', 'D']
['B', 'C', 'E']