首页 > 解决方案 > servlet类与jsp.file之间传递属性时如何解决空指针异常

问题描述

运行时不断出现NullPointerException错误userList.jsp

我正在尝试输出用户对象数组列表的大小:

<%-- 
    Document   : userList
    Created on : 13-Mar-2019, 22:08:54
    Author     : sonia
--%>

<%@page import="java.util.ArrayList"%>
<%@page import="java.util.List"%>
<%@page import="com.mycompany.gartisweb.domain.User"%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<% ArrayList users = (ArrayList)request.getAttribute("users"); %>
<!DOCTYPE html>
<html>
    <head>

        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>List of Users</title>
    </head>
    <body>

                <% users.size(); %>

    </body>
</html>

这就是我的 servlet 类的样子:

public class UserListServlet extends HttpServlet {

    public UserListServlet() {
    }

    //private final UserDao ud = new UserDao();

    /**
     * Processes requests for both HTTP <code>GET</code> and <code>POST</code>
     * methods.
     *
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    @Override
    protected void service(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {

       // List<User> users = new ArrayList();
         //   users = ud.findAllUsers();


        request.setAttribute("users", new UserDao().findAllUsers());
        ServletContext servletContext = getServletContext();
        RequestDispatcher requestDispatcher = servletContext.getRequestDispatcher("userList.jsp");
        //RequestDispatcher rd = request.getRequestDispatcher("userList.jsp");
        requestDispatcher.forward(request, response);
        //rd.forward(request, response);

    }

UserDao 类中的 findAllUsers():

 @Override
public ArrayList<User> findAllUsers() {
    ArrayList<User> userList = new ArrayList<>();
    Connection con;
    con = DBConnection.createConnection();
    Statement statement = null;
    ResultSet rs;
    try {
        con.setAutoCommit(false);
        statement = con.createStatement();
        rs = statement.executeQuery("SELECT * FROM user");
        while (rs.next()) {
           User user = new User();

            user.setId(rs.getInt(1));
            user.setEmail(rs.getString(2));
            user.setPassword(rs.getString(3));
            user.setFirstName(rs.getString(4));
            user.setSurName(rs.getString(5));
            user.setRole(rs.getString(6));
            userList.add(user);
        }
    } catch (SQLException e) {
        throw new RuntimeException(e);
    } finally {

        if (con != null) {
            try {
                con.close();
            } catch (SQLException ex) {
                throw new RuntimeException(ex);

            }
        }
        if (statement != null) {
            try {
                statement.close();
            } catch (SQLException ex) {
                throw new RuntimeException(ex);

            }
        }
    }

    return userList;
}

我在我的代码中找不到错误,有人可以向我解释如何解决这个问题吗?

标签: javamysqljspservletsattributes

解决方案


那是因为您正在使用http://.../userList.jspURL 直接访问 JSP。使用映射到的 URL,UserListServlet以便 servlet 可以设置变量并进行转发。

您可能还想<%= users.size(); %>显示用户数。


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