首页 > 解决方案 > 根据值对关联数组进行排序

问题描述

在数组的每个元素中,第二个值指向元素本身的父元素。例如,在第一个数组中,“City”是根元素,“Area”是第一个子元素,因为第二个“Area”元素 (1) 指向“City.

样本数据

$locations = array(
    3 => array("Building", 2),
    2 => array("Area", 1),
    0 => array("Floor", 3),
    1 => array("City"),
    4 => array("Room", 0),

    13 => array("Building1", 12),
    12 => array("Area1", 11),
    14 => array("Room1", 10),
    10 => array("Floor1", 13),
    11 => array("City1")
);

预期产出

Room > Floor > Building > Area > City

Room1 > Floor1 > Building1 > Area1 > City1

我的解决方案

$route = [];

foreach ($locations as $locationKey => $locationArray) {

    if (!isset($locationArray[1])) continue;

    $nextLocation = $locations[$locationArray[1]][0];
    $route[] = $nextLocation;
}

但是,它不会添加数组中没有给定索引的数组,例如索引 4array("room", 0);

另外,如果一条路线完成,我无法弄清楚如何拆分路线

我得到的输出:

Array
(
[0] => Area
[1] => City
[2] => Building
[3] => Floor
[4] => Area1
[5] => City1
[6] => Floor1
[7] => Building1
)

标签: phparrayssortingassociative-array

解决方案


你可以这样做:

首先保存字典以了解如何获取每个节点和根:

$dic = [];
$roots = [];
foreach($locations as $k => $e) {
    if (count($e) == 2)
        $dic[$e[1]] = $k;
    else
        $roots[] = $k;
}

然后循环所有根并创建路径:

foreach($roots as $root) {
    $path = [];
    $node = $root;
    while (isset($dic[$node])) {
        $path[] = $locations[$node][0];
        $node = $dic[$node];
    }
    $path[] = $locations[$node][0];
    echo implode(",", array_reverse($path)) . PHP_EOL;
}

现场示例:3v4l


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