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python - QGIS渲染shapefile时如何让Python等待

问题描述

我已经为我的代码编写了QGIS 2.8.1可以成功截取一个形状文件的代码，但不幸的是，当我尝试使用多个形状文件时它不起作用。

所以基本上如果我allFiles = ["C:/Shapefiles/Map_00721.shp"]在下面的代码中替换为allFiles = ["C:/Shapefiles/Map_00721.shp", "C:/Shapefiles/Map_00711.shp", "C:/Shapefiles/Map_00731.shp", "C:/Shapefiles/Map_00791.shp", "C:/Shapefiles/Map_00221.shp"]，循环会遍历数组而不等待渲染和快照过程发生。

我已经尝试time.sleep在下面的代码中使用，但它也停止了 shapefile 的渲染，结果没有按预期出现。

import ogr,os
from PyQt4.QtGui import *
from PyQt4.QtCore import *
from qgis.core import *
import qgis.utils
import glob
from time import sleep
import math
import processing
from processing.core.Processing import Processing
from PyQt4.QtCore import QTimer

Processing.initialize()
Processing.updateAlgsList()

OutputFileName = "ABC"    # Temprory global placeholder for filename
canvas = iface.mapCanvas()


def startstuffs():
    qgis.utils.iface.zoomToActiveLayer()    # Zoom to Layer
    scale=canvas.scale()    # Get current Scale
    scale =  scale * 1.5
    canvas.zoomScale(scale)   # Zoomout a bit
    QTimer.singleShot(2000,saveImg)   # Jump to save img

def saveImg():
    qgis.utils.iface.mapCanvas().saveAsImage(OutputFileName)
    QgsMapLayerRegistry.instance().removeAllMapLayers()


# Add array of address below
allFiles = ["C:/Shapefiles/Map_00721.shp"]
filesLen = len(allFiles)

TexLayer = "C:/US_County_NAD27.shp"

for lop in range(filesLen):

    currentShpFile = allFiles[lop]
    currentShpFileName = currentShpFile.strip("C:/Shapefiles/")
    OutputFileName = "C:/ImageOut/" + currentShpFileName + ".png"
    wb = QgsVectorLayer(currentShpFile, currentShpFileName, 'ogr')
    wbTex = QgsVectorLayer(TexLayer, 'CountyGrid', 'ogr')
    QgsMapLayerRegistry.instance().addMapLayer(wb)    # Add the shapefile
    QgsMapLayerRegistry.instance().addMapLayer(wbTex)    # Add the county shapefile
    qgis.utils.iface.setActiveLayer(wb)   # Makes wb as active shapefile

    QTimer.singleShot(3000, startstuffs)    # This start stuffs

print "Done!"

标签： pythonpyqtpyqt4shapefileqgis

解决方案

避免使用time.sleep()，因为这会完全停止你的整个程序。相反，使用processEvents()which 允许您的程序在后台呈现。

import time

def spin(seconds):
    """Pause for set amount of seconds, replaces time.sleep so program doesn't stall"""

    time_end = time.time() + seconds
    while time.time() < time_end:
        QtGui.QApplication.processEvents()

这种方法应该可以很好地快速修复，但从长远来看，它可能会产生难以跟踪的问题。最好使用带有事件循环的 QTimer 作为永久解决方案。

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